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c - 字符串数组排序(唯一字符串)

转载 作者:行者123 更新时间:2023-11-30 19:44:38 24 4
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我有从文本中打印单词的代码,但需要对其进行打乱。代码可以运行,但单词会重复。我应该改变什么才能只获得独特的单词?

#define MAX_MESSAGES (3)
#define MAX_MESSAGE_LEN (150)

static char message[MAX_MESSAGES][MAX_MESSAGE_LEN] = {{'\0'}};
static char buffer[MAX_MESSAGE_LEN] = {'\0'};

int main()
{
/*declare and initialise variable*/
int i=0;
int j;

FILE *file_in;
if( NULL == (file_in=fopen("test.txt", "r") ) )
{ // then, fopen failed
perror( "fopen failed for test.txt" );
exit( EXIT_FAILURE );
}

// implied else, fopen successful

srand(time(NULL));

/*stores and prints the data from the string*/
while( (i<MAX_MESSAGES) && fgets(buffer,150,file_in) )
{
strcpy(message[i],buffer);
i++;
} // end while

printf("\ndisplay %d messages in random order\n", MAX_MESSAGES);
printf("with possible repeated messages and skipped messages\n");
for( i=0; i < MAX_MESSAGES; i++)
{
j = rand() % MAX_MESSAGES;
printf("%s\n",message[j]);
} // end for

return 0;
}

我知道 Fisher-Yates shuffle 方法,我找到了如何描述函数,但我不明白如何在我的代码中调用它。

void shuffle(int *array, size_t n)
{
if (n > 1) {
size_t i;
for (i = 0; i < n - 1; i++) {
size_t j = i + rand() / (RAND_MAX / (n - i) + 1);
int t = array[j];
array[j] = array[i];
array[i] = t;
}
}
}

最佳答案

重新提交答案。由于某种原因,我几乎更改了您问题代码的每一行。我建议你逐行浏览并比较。特别是,您并没有离开使用 #define 值,并且您的循环基于最大容量而不是实际读取的行数。

我添加了之前发布的随机但独特的输出。

请注意,fgets() 会留下尾随的换行符,如输出的双倍行距所示。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

#define MAX_MESSAGES 20
#define MAX_MESSAGE_LEN 150

char message[MAX_MESSAGES][MAX_MESSAGE_LEN+1]; // allow 1 spare
char buffer [MAX_MESSAGE_LEN+1];
int pool [MAX_MESSAGES];

int main()
{
int size=0, n;
FILE *file_in;
if (NULL == (file_in=fopen("test.txt", "rt"))) {
perror ("fopen failed for test.txt");
exit (EXIT_FAILURE);
}
while (size<MAX_MESSAGES && fgets(buffer, MAX_MESSAGE_LEN, file_in))
strcpy (message[size++],buffer);
fclose (file_in); // was omitted

for (n=0; n<size; n++) // set up message index pool
pool [n] = n;
srand((unsigned)time(NULL));

printf ("\ndisplay %d messages in random order\n", size);
printf ("with possible repeated messages and skipped messages\n");

while (size) { // print and remove random message
n = rand() % size;
printf("%s\n",message [ pool[n] ]);
pool [n] = pool [--size]; // remove index from pool
}
return 0;
}

关于c - 字符串数组排序(唯一字符串),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27815759/

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