C++。将二维指针数组传递到函数时遇到问题

Question

这个问题已经有答案了:

Can a local variable's memory be accessed outside its scope? (20 个回答)

已关闭 7 年前。

我正在制作一个基于文本的小型游戏。如果我将它放在主函数中，我的代码就可以工作，但是当尝试将其放入它自己的函数中时，它会用垃圾数据填充我的字符串，最终导致程序在尝试读取数据时崩溃。

所以这是我的问题，我应该如何将 Room 指针的 2D 数组传递到我的函数中，以便我可以获得与仅将代码保留在主函数中相同的结果。

以下是当前在我的函数中的代码，当不在函数中时，它可以正常工作。

void InitialiseLevel(int CurrentLevel, Room *Level[2][2]){
if (CurrentLevel == 1){

    JumpScareRoom JSRoom1;
    Room *room1 = &JSRoom1;
    JSRoom1.SetExits("se");
    JSRoom1.SetDescriptions("I am a jumpscare room.", "I am a boring room 1");
    JSRoom1.SetSouthMessages("There is a door to the SOUTH", "You exit through the SOUTH door.");
    JSRoom1.SetEastMessages("There is a door to the EAST", "You exit through the EAST door.");
    Room room2;
    room2.SetExits("ws");
    room2.SetDescriptions("I am a cool room 2", "I am a boring room 2");
    Room room3;
    room3.SetExits("ne");
    room3.SetDescriptions("I am a cool room 3", "I am a boring room 3");
    Room room4;
    room4.SetExits("wn");
    room4.SetDescriptions("I am a cool room 4", "I am a boring room 4");

    Level[0][0] = room1;
    Level[0][1] = &room2;
    Level[1][0] = &room3;
    Level[1][1] = &room4;
}
}

我的 main 将数组初始化为

Room *Rooms[2][2] = {};

然后它使用调用该函数

InitialiseLevel(1, Rooms); // set up level 1.

我尝试了很多不同的方法，例如使用

void InitialiseLevel(int CurrentLevel, Room **Level[2][2])

和

void InitialiseLevel(int CurrentLevel, Room *(&Level)[2][2])

但是我似乎错过了一些重要的事情。

Answer 1

JumpScareRoom JSRoom1;

是一个本地对象，当你超出函数范围时，它就会失效。相反，您可以使用:

JumpScareRoom *pJSRoom1 = new JumpScareRoom();
Room *room1 = JSRoom1;
JSRoom1->SetExits("se");
JSRoom1->SetDescriptions("I am a jumpscare room.", "I am a boring room 1");
JSRoom1->SetSouthMessages("There is a door to the SOUTH", "You exit through the SOUTH door.");
JSRoom1->SetEastMessages("There is a door to the EAST", "You exit through the EAST door.");
...