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我正在使用 switch case，并且在 case 中有循环和 if/else。即使没有检测到错误，我仍然无法弄清楚为什么它不会在文件中显示正确的汽车类型。令人沮丧的是我的预产期是明天。编码位于案例编号 3 处。其目的是将信息写入 customer_info 文件。这是我的编码和输出:

编码:

    #include<stdio.h>

void display_cars();
float total_price_A(int);
float total_price_B(int);
float total_price_C(int);
void readcustomerrent_info();

main()
{

   int i,selection,answer;
   int noofcustomer;
   char car;

   printf("Number of customers: ");
   scanf("%d", &noofcustomer);

   char fullname[noofcustomer][50], ic[noofcustomer][50], phonenum[noofcustomer][50], license[noofcustomer][50];
   int  renthour[noofcustomer];
   float total_price[noofcustomer];

   printf("\t==================================================");
   printf("\n\t\t         CAR RENTAL SYSTEM\n");
   printf("\t==================================================\n\n");

   do
   {

   printf("\t\t     ----..Main Menu..----\n\n\t1 - Insert Customer Information \n\t2 - Select Car & Hour \n\t3 - Read Customer and Rent Information\n");

   printf("\nChoose your menu selection\n");
   scanf("%d", &selection);

   switch(selection)
   {
     case 1: printf("----Please fill in the information below----\n\n");



             for(i=0;i<noofcustomer;i++)
             {
                printf("Your Name : ");
                fflush(stdin);
                gets(fullname[i]);


                printf("Your IC : ");
                fflush(stdin);
                gets(ic[i]);


                printf("Your Telephone Number : ");
                fflush(stdin);
                gets(phonenum[i]);


                printf("Your License Number : ");
                fflush(stdin);
                gets(license[i]);

                printf("\n\n");


             }

             break;


    case 2:  printf("\n----Select Car & Hour----\n");

             display_cars();
             for(i=0;i<noofcustomer;i++)
             {
                printf("Choose the car\n");
                fflush(stdin);
                scanf("%c", &car);

               printf("Enter the rent hour : ");
               scanf("%d", &renthour[i]);

               if(car=='A')
               {
                   total_price[i] = total_price_A(renthour[i]);
                   printf("\nTotal Price For The Rent: RM%.2f", total_price[i]);
                   printf("\n\n");

               }
               else if(car=='B')
               {
                   total_price[i] = total_price_B(renthour[i]);
                   printf("\nTotal Price For The Rent: RM%.2f", total_price[i]);
                   printf("\n\n");

               }
               else if(car=='C')
               {
                   total_price[i] = total_price_C(renthour[i]);
                   printf("\nTotal Price For The Rent: RM%.2f", total_price[i]);
                   printf("\n\n");
               }
               else
               {
                   printf("\nThere's no such thing in our system. Kindly please try another letter\n");
                   printf("\n\n");
               }
             }


             break;



    case 3:  printf("\n---Receipt and Read Customer Information----\n");

             FILE *myfile;
             myfile = fopen("customer_info.txt","w");

             for(i=0;i<noofcustomer;i++)
             {
               fprintf(myfile,"Name : %s",fullname[i]);
               fprintf(myfile,"\nIC : %s",ic[i]);
               fprintf(myfile,"\nTelephone Number : %s",phonenum[i]);
               fprintf(myfile,"\nLicense Number : %s",license[i]);

               if(car=='A')
               {
                   fprintf(myfile,"\nCar : Audi");
                   fprintf(myfile,"\nTotal Price : %.2f",total_price[i]);
                   fprintf(myfile,"\n\n");
               }
               else
                   if(car=='B')
                   {
                   fprintf(myfile,"\nCar : Corolla");
                   fprintf(myfile,"\nTotal Price : %.2f",total_price[i]);
                   fprintf(myfile,"\n\n");
                   }
                  else
                     if(car=='C')
                    {
                      fprintf(myfile,"\nCar : Axia");
                      fprintf(myfile,"\nTotal Price : %.2f",total_price[i]);
                      fprintf(myfile,"\n\n");
                    }
                    else
                   {
                      fprintf(myfile,"\nCar : -");
                      fprintf(myfile,"\nTotal Price : -");
                      fprintf(myfile,"\n\n");
                   }
             }

              fclose(myfile);

             //readcustomerrent_info();

             break;


   default:  printf("Your entered invalid selection.");

   }

    printf("\n\nDo you like to continue? (Yes-1/No-0): ");
    scanf("%d", &answer);

  }while(answer == 1);

   printf("\nExit the system..... THANK YOU FOR USING THE SYSTEM\n\n\n");
}

它在第二个循环信息中为所有客户显示了汽车类型，但计算效果很好:(希望你们能帮助我。将不胜感激!!

Answer 1

您需要将所有客户的汽车类型信息保存在一个数组中。否则，您所有客户的汽车类型将与最后一个客户的汽车类型相同。

您需要进行以下更改:

...

printf("Number of customers: ");
scanf("%d", &noofcustomer);

...

char car[noofcustomer];//holds the car type for each customer 

...

case 2:  printf("\n----Select Car & Hour----\n");
         display_cars();
         for(i=0;i<noofcustomer;i++)
         {
            printf("Choose the car\n");
            fflush(stdin);
            scanf("%c", &car[i]);//save the car type for each customer

            ...

            if(car[i]=='A')//use an index
            {
            ...

case 3:  printf("\n---Receipt and Read Customer Information----\n");

         FILE *myfile;
         myfile = fopen("customer_info.txt","w");

         for(i=0;i<noofcustomer;i++)
         {
           if(car[i]=='A')//use the previously populated array of car types for each customer
           {
              ...