c - 如何将大十进制值转换为二进制

Question

我有一个简单的程序，其中程序接收来自文件的输入并将十进制转换为二进制并计算二进制形式的个数？现在对于小值来说是可以的对于像 15755645551 这样的巨大值，它显然不起作用有人知道如何解决这个问题吗？任何人都可以尝试使用我的代码吗？谢谢你!!这是我的代码:

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>
#define BUFFER 25

long number_read = 0;
long number_of_ones = 0;
long remainder_value = 0;
long binary = 0;
long base = 0;
long buff[BUFFER];

int main()
{
    FILE *fp;                 //file pointer fp
    fp = fopen("File.txt", "r+");

    while (fgets(buff, sizeof(buff), fp) != NULL)
    {
        number_read = atoi(buff);                   //ASCII to integer
        printf("\nnumber is=%d", number_read);
        while (number_read > 0)
        {
            remainder_value = number_read % 2;
            /*  To count no.of 1s */
            if (remainder_value == 1)
            {
                number_of_ones++;
            }

            binary = binary + remainder_value * base;
            number_read = number_read / 2;
            base = base * 10;
        }
        printf("\nNo.of 1's in It's binary representation is = %d\n", number_of_ones);
        number_of_ones = 0;
    }
    fclose(fp);
    return 0;
}

Answer 1

因为“long”类型与“int”类型一样占用4个字节。您应该将其更改为“long long”类型。