c - 奇怪的语句循环

Question

#include<stdio.h>
#include<stdlib.h>
#include<time.h>


//prototype
void input(int *);
void statements(int, int);
void print(int, int *);




void main()
{
   int num, guess;
   time_t t;

   srand((unsigned) time(&t));
   num=rand()% 100+1;

   printf("%d\n", num);

   input(&guess);
   statements(num, guess);

}



void input(int *guess)
{
   printf("Guess a number between 1 and 100: ");
   scanf("%d", &*guess);
}

void statements (int num, int guess)
{


   if(guess==num)
      printf("You have guessed correct! The number is: %d", num);
   else if(guess>num)
   {
      printf("The number you have guessed is too big\n");
      print(num, &guess);

   }
   else if(guess<num)
   {
      printf("The number you have guessed is too small\n");
      print(num, &guess);
   }

}




    void print( int num, int *guess)
    {

        printf("Guess again: ");
        scanf("%d", &*guess);
        statements(num, guess);
    }

基本上，我正在为猜谜游戏编写一个程序作为作业，用户不断尝试，直到他/她的答案正确为止；但是，当我执行它时，如果用户第一次没有得到正确的结果，程序会一直告诉他数字太大，无论如何。不允许循环例子:85猜一个 1 到 100 之间的数字:90您猜到的数字太大再猜一下:20您猜到的数字太大再猜一下:

如有任何帮助，我们将不胜感激

Answer 1

除了评论指出的问题之外，您对递归的使用也是一个潜在的问题。如果用户一直猜测错误，最终将导致调用堆栈崩溃。另外，指针引用、取消引用的序列，即 &* 不会执行任何操作，因此您应该将其取出。因此，使用 while 循环而不是使用递归的正确代码如下所示:

void statements (int num, int guess)
{
    while (guess!=num) { 
        if(guess>num) {
            printf("The number you have guessed is too big\n");
            print(num, &guess);
        } else if(guess<num) {
            printf("The number you have guessed is too small\n");
            print(num, &guess);
        }
    }
    printf("You have guessed correct! The number is: %d\n", num);
}

void print( int num, int *guess)
{
    printf("Guess again: ");
    scanf("%d", guess);
}