c - 陷入 getIntLimited 函数中

Question

我遇到了陷入 getIntLimited 函数的问题。在调整数量中，我需要它检查用户是否输入了正确的数字，而不是多于或少于所需的数字，而不是字母。我没有对“库存”选项这样做，只在“检查”选项中这样做。但我的第一个问题是我必须输入数字两次才能得到响应，第二个问题是我无法退出 getIntLimited 循环。这是输出的图像:

以及我的代码部分:

void GroceryInventorySystem(void){
    struct Item Items[MAX_ITEM_NO];
    int opt, records;
    int loop = 0;
    welcome();
    while(!loop){
        if(opt == 3){
            adjustQuantity(Items, records, CHECKOUT);
            saveItems(Items, DATAFILE, records);
            if(0 == saveItems(Items, DATAFILE, records)){
                printf("Could not update data file %s\n", DATAFILE);
            }
            pause();
        }
}
int getInt(void){ // Check if user entered the character and breaks, returns the value if a number // 
    char letter = 'x';
    int value;
    while(1){
        scanf("%d%c", &value, &letter);
        if(letter != '\n'){
            printf("Invalid integer, please try again: ");   
            flushKeyboard();
        }else{
            return value;
        }
    }
}

int getIntLimited(int lowerLimit, int upperLimit){ // Check if user typed the value higher/lower and repeats. Returns the value if user entered the right number //
    int Value;
    while(1){
        Value = getInt();
        if(Value <= lowerLimit || Value >= upperLimit){
            printf("Invalid value, %d < value < %d: ", lowerLimit, upperLimit); 
        }else{
            return Value;
        }
    }
}
void adjustQuantity(struct Item item[], int NoOfRecs, int stock) {
    int check, sku, index, opt;
    char tostock[] = "to stock", tocheck[] = "to checkout";
    printf("Please enter the SKU: ");
    scanf("%d", &sku);
    check = locateItem(item, NoOfRecs, sku, &index);
    if (check == 0) {
        printf("Item not found!\n");
    } else {
        displayItem(item[index], FORM);
        if (stock == STOCK) {
            printf("Please enter the quantity %s; Maximum of %d or 0 to abort: ", tostock, MAX_QTY - item[index].quantity);
            scanf("%d", &opt);
            if (opt == 0) {
                printf("--== Aborted! ==--\n");
            } else {
                item[index].quantity += opt;
                printf("--== Stocked! ==--\n");
            }
        } else {
            printf("Please enter the quantity %s; Maximum of %d or 0 to abort: ", tocheck, item[index].quantity);
            scanf("%d", &opt);
            if (opt == 0) {
                printf("--== Aborted! ==--\n");
            } else if (item[index].quantity < opt){
                opt = getIntLimited(item[index].quantity, 0);
            } else {
                item[index].quantity -= opt;
                printf("--== Checked out! ==--\n");
                if (item[index].quantity <= opt) {
                    printf("Quantity is low, please reorder ASAP!!!\n");
                }
            }
        }
    }
}

Answer 1

我在 opt = getIntLimited(0, item[index].quantity); 中犯了一个错误，它应该是相反的 opt = getIntLimited(item[index].quantity, 0); 现在，只要我在 0 和 5 之间键入正确的数字，它就会退出循环。我还使用了 opt = getIntLimited(0, item[index].quantity); 而不是 scanf，并删除了 else if 语句