改变指针的值

Question

我刚刚开始学习C语言，我有一个基本问题。

#include <stdio.h>

int main() {
    // These variables have been assigned hidden values:
    int secret;
    int *another_secret;

    // Declare a variable named secret_pt and make it point to secret:

    // Add the value at the address pointed to by another_secret to the
    // value at the address pointed to by secret_pt.
    // Do not change the address assigned to secret_pt, and don't explicitly set secret.

    return 0;
}

这是我的方法；

#include <stdio.h>

int main() {
    // These variables have been assigned hidden values:
    int secret;
    int *another_secret;

    // Declare a variable named secret_pt and make it point to secret:

     //  int *secret_pt;
    //secret_pt = &secret;
    int *secret_pt = &secret;

    // Add the value at the address pointed to by another_secret to the
    // value at the address pointed to by secret_pt.
    // Do not change the address assigned to secret_pt, and don't explicitly set secret.

    int *secret = *another_secret;

    return 0;
}

但是我遇到了重新定义错误，这是有道理的，但我不知道如何解决它。

Answer 1

您将获得两个地址:secret_pt 和 another_secret。系统会要求您将它们的内容添加在一起并将结果存储到 secret_pt 指向的任何位置。这恰好是 secret ，但您不应该直接分配给它。

通过使用 * 运算符取消引用指针来访问指针的内容。因此，secret_pt 地址处的值为 *secret_pt，类似地，another_secret 地址处的值为 *another_secret >。您可以将它们添加在一起。

请记住，*secret_pt 只是secret，您可以使用它来存储secret，而无需实际使用名称 secret 。