C 字符串打印超出范围

Question

只要在其中找到子字符串 aaa，此代码就会中断主字符串 stringone。此代码正在执行此操作，但它打印出边界并且不会在空字符处停止。

我得到的输出是这样的

who cares if 
one more light goes out 
in the sky of a million 
stars, 
well i do if the star is you 
;<@����P����p���Xz��������p���0zRx
                                            ����+zRx
                                                              �$����FJ
                                                                           �?;*}D���� \�����A�C
  D|���eB�B�E �B(�H0�H8�M@r8A0A(B BB�8����p

我不明白为什么，我是否跳过更新字符串的行中的 NULL 字符？

#include<stdio.h>
#include<string.h>

int main()
{

    char *stringone = "who cares if aaa one more light goes out aaa in the sky of a million aaa stars, aaa well i do if the star is you \0";

    char *breaker = "aaa";

    while(stringone)
    {
        while(stringone != strstr(stringone, breaker) || stringone == NULL)
        {
            printf("%c",*stringone);
            stringone++;
        }

        stringone = stringone + strlen(breaker) + 1;
        printf("\n");
    }
    return 0;
}

Answer 1

您应该使用 strtok 函数。请参阅示例:

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

int main() {
    char stringone[200] = "who cares if aaa one more light goes out aaa in the sky of a million aaa stars, aaa well i do if the star is you";
    char breaker[10] = "aaa";
    char *token = strtok(stringone, breaker);

    while (token != NULL) {
        printf("\n %s", token);
        token = strtok(NULL, breaker);
    }
    return 0;
}