以快速简单的方式将临时结构复制到静态结构

Question

这个问题已经有答案了:

Assign one struct to another in C (6 个回答)

已关闭 4 年前。

如何将临时结构复制到实际的静态结构？

typedef struct MyStruct {
int a;
int b;
int c:
}MyStruct ;
Mystruct structMain;


funcCopyTempToMain(Mystruct structTemp)
{
    structMain = structTemp;
}

类似这样的事情..以这种方式复制整个结构是否合法？我只知道它对于指针来说是合法的。

Answer 1

使用赋值运算符进行复制最好与上面代码中的操作相同。它很容易阅读，而不是将每个成员复制到静态结构 main

来自https://stackoverflow.com/a/9127315/8701568

An important note about the copying: It's a shallow copy, just like with memcpy. That means if you have e.g. a structure containing pointers, it's only the actual pointers that will be copied and not what they point to, so after the copy you will have two pointers pointing to the same memory.