c - 为什么没有输出，EOF 的值是多少？

Question

这个问题已经有答案了:

End of File (EOF) in C (3 个回答)

已关闭 4 年前。

我正在测试《C 编程语言》一书中的代码，我想知道 EOF 的值是什么以及如何找到它？我尝试使用某种指针引用该值，但我只是得到一个 const 指针错误。无论如何，下面是我的代码，我想知道为什么点击输入后没有输出:

#include <stdio.h>

#define IN 1 /*inside a word*/
#define OUT 0 /*outside a word*/

/* count lines, words, and characters in input*/
main()
{
  int c, nl, nw, nc, state;

  state = OUT;

  nl = nw = nc = 0;
  while ((c = getchar()) != EOF){
    ++nc;
    if (c == '/n')
      ++nl;
    if (c == ' ' || c == '\n' || c == '\t')
      state = OUT;
    else if (state == OUT){
      state = IN;
      ++nw;
    }
  }
  printf("%D %D %D\n", nl, nw, nc);
}

Answer 1

#include <stdio.h>

#define IN 1 /*inside a word*/
#define OUT 0 /*outside a word*/

/* count lines, words, and characters in input*/
int main(void)
{
  int c, nl, nw, nc, state;

  state = OUT;

  nl = nw = nc = 0;
  while ((c = getchar()) != EOF){
    ++nc;
    if (c == '\n')
      ++nl;
    if (c == ' ' || c == '\n' || c == '\t')
      state = OUT;
    else if (state == OUT){
      state = IN;
      ++nw;
    }
  }

  printf("%d %d %d\n", nl, nw, nc);
  printf("EOF = %d\n", EOF);
  return 0;
}