javascript - 日期之间的差异，四舍五入到最近的分钟

Question

日期之间的差异要四舍五入到最近的分钟。date1、date2 向下或向上舍入。返回的结果已经四舍五入到整分钟。我可以修改date1,date2。不要修改已经返回的结果

date2-date1

代码在这里:https://stackblitz.com/edit/react-azau4g

示例:

第一步

this.state = {
  date1: "2019-06-29 21:25:38+00",
  date2: "2019-06-29T21:25:40.000+00:00"
}

round = (item) => {
  var m = moment(item);

  var roundUp = (m.second() || m.millisecond() ? m.add(1, 'minute').startOf('minute') : m.startOf('minute')).toISOString();
  return roundUp;
}

differentTime = {
    date1: this.state.date1.toISOString(),  
    date2: this.round(this.state.date2)   //return "2019-06-29T21:26:00.000+00:00"
}

第二步

预期效果:

data2 - data1 = 1 分钟

---

示例 2

 this.state = {
      date1: "2019-06-29 21:25:01+00",
      date2: "2019-06-29T21:27:20.000+00:00"
    }



 differentTime2 = {
        date1: this.state.date1.toISOString(), 
        date2: this.round(this.state.date2)   //return "2019-06-29T21:28:00.000+00:00"
    }

预期效果:

date2 - date1 = 3 分钟

Answer 1

您似乎想要一个函数，将一个日期减去另一个日期并将差值四舍五入到最接近的分钟。

这不能通过问题中的 round 函数这样的单个参数来完成；您需要一个将两个日期都作为参数的函数。

我对 moment 不太熟悉，但这里有一个应该适用于内置日期的函数。

编辑:根据 OP 的评论，我更新了函数以修改 d2 而不是返回 diff。

    MS_IN_MINUTES = 60000;

    roundAway = (d1, d2) => {
      let diff = d2 - d1 // Difference in milliseconds (+ or -)
      let positive = diff > 0 // Whether we should add later
      diff = Math.abs(diff) // Difference in milliseconds (+)
      diff = diff / MS_IN_MINUTES // Difference in minutes (not rounded)
      diff = Math.ceil(diff) // Difference in minutes (rounded up)
      let roundedAway = d1.getTime()
      if (positive) {
          roundedAway += diff * MS_IN_MINUTES
      }
      else {
          roundedAway -= diff * MS_IN_MINUTES
      }
      d2.setTime(roundedAway)
    }
    
    let date1 = new Date("2019-06-29 21:25:38+00");
    console.log('date1:', date1)

    let date2 = new Date("2019-06-29T21:25:40.000+00:00");
    console.log('date2:', date2)

    let date3 = new Date("2019-06-29T21:24:36.000+00:00");
    console.log('date3:', date3)

    console.log('Unchanged date1:', date1);

    roundAway(date1, date2);
    console.log('Rounded date2:', date2);

    roundAway(date1, date3);
    console.log('Rounded date3:', date3);

希望对您有所帮助!