c# - 我如何计算使用 DateTime.Now 调用该方法的速度？

Question

我将给出方法代码的顶部，因为整个代码很长，在这种情况下不需要。

static int tickCountLength = 1000;
        int[] tickCounts = new int[tickCountLength];
        int numberOfTicks = 0;
        TimeSpan dtn;

        void DoCaptureRenderTarget(Device device, string hook)
        {
            //Environment.TickCount-->array

            tickCounts[numberOfTicks] = Environment.TickCount;
            numberOfTicks++;

            DateTime start1 = DateTime.Now;
            DateTime end1 = DateTime.Now;
            this.DebugMessage("Capture Time Testing " + (end1 - start1).ToString());
            dtn = end1 - start1;
            if (dtn.Seconds > 0)
            {
                string fffff = "fgf";
            }
            if (numberOfTicks >= tickCountLength)
            {

                StreamWriter w = new StreamWriter(@"c:\Milliseconds\TickCount.txt", true);
                foreach (int tick in tickCounts)
                {
                    w.WriteLine("TickCount === > " + tick.ToString());

                }
                w.Close();
                numberOfTicks = 0;
            }

该方法每 1 毫秒或 20 毫秒调用一次，不确定实时时间。所以我添加了这部分试图计算:

DateTime start1 = DateTime.Now;
            DateTime end1 = DateTime.Now;
            this.DebugMessage("Capture Time Testing " + (end1 - start1).ToString());
            dtn = end1 - start1;
            if (dtn.Seconds > 0)
            {
                string fffff = "fgf";
            }

但这肯定是错误的，end1 和 start1 之间的时间是 00:00:00:00我如何以毫秒为单位计算方法每次调用的时间？

也许:每次都使用 DateTime.Now.Millisecond 并手动从前一个中减去(通过查看)？不知道该怎么做。

Answer 1

使用StopWatch

例子:

Stopwatch stopWatch = new Stopwatch();
stopWatch.Start();
Thread.Sleep(10000);// or whatever code you want to calculate elapsed time.
stopWatch.Stop();
// Get the elapsed time as a TimeSpan value.
TimeSpan ts = stopWatch.Elapsed;

// Format and display the TimeSpan value. 
string elapsedTime = String.Format("{0:00}:{1:00}:{2:00}.{3:00}",
    ts.Hours, ts.Minutes, ts.Seconds,
    ts.Milliseconds / 10);
Console.WriteLine("RunTime " + elapsedTime);