javascript - 如何从 yaml 文件为 Kubernetes nodejs API 客户端生成 `V1Job` 对象？

Question

我之前在 python 中使用过:

    with open(path.join(path.dirname(__file__), "job.yaml")) as f:
        body= yaml.safe_load(f)

        try:
            api_response = api_instance.create_namespaced_job(namespace, body)

查看 nodejs api 客户端的源代码:

    public createNamespacedJob (namespace: string, body: V1Job, includeUninitialized?: boolean, pretty?: string, dryRun?: string, options: any = {}) : Promise<{ response: http.IncomingMessage; body: V1Job;  }> {

如何生成 V1Job？

---

我已经尝试了下面的方法，但得到了一条非常详细的错误消息/响应:

const k8s = require('@kubernetes/client-node');
const yaml = require('js-yaml');
const fs   = require('fs');

const kc = new k8s.KubeConfig();
kc.loadFromDefault();

const k8sApi = kc.makeApiClient(k8s.BatchV1Api);

var namespace = {
    metadata: {
        name: 'test123',
    },
};

try {
    var job = yaml.safeLoad(fs.readFileSync('job.yaml', 'utf8'));

    k8sApi.createNamespacedJob(namespace, job).then(
        (response) => {
            console.log('Created namespace');
            console.log("Success!")
        },
        (err) => {
            console.log(err);
            console.log(job);
            console.log("Err")
        },
    );

} catch (e) {
    console.log(e);
}

Answer 1

1. V1Job 似乎是一个普通的对象，所以下面的工作。
2. 命名空间必须是一个字符串而不是一个对象...

const k8s = require('@kubernetes/client-node');
const yaml = require('js-yaml');
const fs   = require('fs');

const kc = new k8s.KubeConfig();
kc.loadFromDefault();

const k8sApi = kc.makeApiClient(k8s.BatchV1Api);

try {
    var job = yaml.safeLoad(fs.readFileSync('job.yaml', 'utf8'));

    k8sApi.createNamespacedJob("default", job).then(
        (response) => {
            console.log("Success")
        },
        (err) => {
            console.log(e);
            process.exit(1);
        },
    );

} catch (e) {
    console.log(e);
    process.exit(1);
}