计算平均值等的C程序

Question

我今天在老师的帮助下在类里面编写了这段代码，但我现在回家了，需要指导，我不知道接下来我应该做什么才能让它至少编译

目标是:

创建菜单输入一个数字(选项A)显示平均值(选项 B)显示最大和最小数字(选项C和D)显示输入的所有数字的总数(选项 E)显示输入的数字总数(选项F)然后退出(选项 G)

这是我到目前为止所拥有的，如果它很困惑，我很抱歉

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

//int getNumber (aNumber) {
 //   printf("Enter an integer between 0 and 1000.\n");
//    scanf("%i", &aNumber);
 //   int result;
 //   }
char getMenuLetter();
int getNumber();
//declare variables

int aNumber = 0;
float avg = 0.0;
int high = -1;
int low = 1001;
int total = 0;
int count = 0;
char getChoice = 'x';

int main() {

//proptotype functions



do {
    getChoice = getMenuLetter();

    switch (getChoice)
           case 'A':
           aNumber = getNumber();
           count++;
           total += aNumber;
           low = testLow(aNumber, low)
           high = testHigh(aNumber, high);
                        break;
           case 'B';
           avg = (double) total/count; //display avg
           printf("The average is %.2f", avg);
                       break;
           case 'C':
           high = getHigh();
           printf("The highest value of all the numbers entered is %i.\n", high); //display highest number
                       break;
           case 'D':
           low = getLow;
           printf("The lowest value of all the numbers entered is %i.\n", low); //displayer lowest value
                       break;
           case 'E':
           printf("The total of all the numbers entered is %i.\n", total);
                       break;
           case 'F':
           printf("The amount of numbers entered so far is %i.\n", count);
           case 'G';
                       break: //end switch


} while (userChoice != 'G');

}

int testLow(int n) {
    int result;

    if (n < low)
          result = n;
    else

    return 0;

} //End of main

char getMenuLetter() {
     char result;
     system("cls") //clear the screen.

     printf("*************************************************\n");
     printf("A) Enter a number between 0 and 1,000\n");
     printf("B) Display the average\n");
     printf("C) Display the highest value entered\n");
     printf("D) Display the lowest value entered\n");
     printf("E) Display the sum of all numbers\n");
     printf("F) Display the count of all numbers entered\n");
     printf("G) Quit the program\n");
     printf("*************************************************\n");
     scanf("%c", &result);
     result =toupper(result);
///print f %c 
//system pause

if (result != 'A' || result != 'B' || result !='C' || result !='D' || result !='E' || result != 'F' || result !='G'){
            printf("You must enter A - G only! \n)");
            system("pause");
 } //end if

} while(result != 'A' || result != 'B' || result !='C' || result !='D' || result !='E' || result != 'F' || result !='G');
     return result;
     //end of GetMenuLetter

Answer 1

这是我的建议:

1. 首先编译您的程序。您的编译器将返回大部分错误(至少是重要的错误)。
2. 注意 curl 基数的使用。在 C(以及许多其他语言)中，编译器将线性处理其他行后面的行。大括号导致多维解释。作为编程初学者，您应该尽可能练习使用大括号，这样您就可以养成分隔指令的习惯。另外，您应该密切注意左花括号与右花括号的匹配。有关更多信息，您应该查看C Standard, 6.8: Statements and Blocks .
3. 您的 switch() block 应以 default: 值结尾，以防您做出意外选择。
4. 我不建议将函数原型(prototype)放入 main() 过程中。它与范围有关。请查看标准的第 6.2.1 节。

2 For each different entity that an identifier designates, the identifier is visible (i.e., can be used) only within a region of program text called its scope. Different entities designated by the same identifier either have different scopes, or are in different name spaces. There are four kinds of scopes: function, file, block, and function prototype. (A function prototype is a declaration of a function that declares the types of its parameters.)

我不知道还能告诉你什么。按顺序尝试我建议的方法。但请务必阅读该标准。最后的建议是:尝试以更有序的方式进行编程。如果您继续编码的目的是希望在完成时能够阅读到一些内容，那么您的代码就不会看起来那么草率。

祝你好运。