c - 获取数组声明错误

Question

我有一个名为arr_[6]的数组，有一个包含六个字符串的想法......但是当我声明这个数组时，编译器会抛出错误。

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i;

    char arr_1[]= {"My_name","your Name", "His Name"};


    char *arr_p;

    arr_p = malloc(sizeof(char)*6);

    arr_p = arr_1;

    printf("%s\n",*arr_p);


    system("PAUSE"); 

    return 0; 
}

显示的错误如下:

> main.c: In function `main': main.c:9: error: excess elements in char
> array initializer main.c:9: error: (near initialization for `arr_1')
> main.c:9: error: excess elements in char array initializer main.c:9:
> error: (near initialization for `arr_1')
> 
> make.exe: *** [main.o] Error 1

请帮助我!

Answer 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i;
    const char *arr_1[]= {"My_name","your Name", "His Name"}; // has to be an array of <char *>

    //arr_p is not necessary

    printf("%s\n",*arr_1); // will print the first string, "My_name"
    printf("%s\n",arr_1[1]); // will print the second string, "your Name"
    printf("%s\n",arr_1[2]); // will print the third string, "His Name"
    system("PAUSE"); 
    return 0; 
}