c - 输入验证分配并显示是否为二维字符数组

Question

我正在尝试在 C 中填充二维数组。一切正常，但分配给数组的值未打印。

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h> 
#include <string.h> 

main()
{
    char parkingspace[25][4];
    char CarReg[7], validreg[7];
    int row, position;

    printf( "Enter the car Registration number \n" );
    fgets( CarReg, sizeof( CarReg ), stdin );
    if( isdigit( CarReg[0] )&& isdigit( CarReg[1] ) && (CarReg[2]=='H' ) && ( CarReg[3]=='I' ) && ( CarReg[4]=='R' ) && ( CarReg[5]=='E' ))
    {
        puts( "Valid Registration \n" );
        printf( "==================================================\n\n\n" );
    }
    else
    {   
        puts( "Invalid registration .\n Please put a value of two digits followed by the word HIRE! in caps" );
    }
    printf( "You entered: %s\n", CarReg );
    if( isdigit( CarReg[0] )&& isdigit( CarReg[1] ) && ( CarReg[2]=='H' ) && (CarReg[3]=='I' ) && ( CarReg[4]=='R' ) && ( CarReg[5]=='E' ))
    {
        strcpy(validreg, CarReg);
        printf( "Accepted Car Reg is : %s\n\n\n\n", validreg );
        printf( "==================================================\n\n\n");
    }
    for (row=1; row<26; row++)
    {
        for (position=1;position<5; position++)
        {
            parkingspace[row][position]=validreg;
            printf("parkingspace \t row[%d] position[%d] =[ %c ]\n", row,position,parkingspace[row][position]);
        }
    }   
}

Answer 1

您遇到的一个问题是数组的索引从零到数组大小减一。因此，row 的有效索引是 0 到 24，而不是 1 到 25你会的。

<小时/>

另一个问题是您尝试将字符数组分配给单个字符:

parkingspace[row][position]=validreg;

如果您只想在 parkingspace[row] 中使用 validreg 的前四个字符，那么请执行以下操作:像这样的内循环:

for (position=0; position < 4; position++)
{
    parkingspace[row][position] = validreg[position];
    printf("parkingspace \t row[%d] position[%d] =[ %c ]\n", row, position, parkingspace[row][position]);
}