c - 如何在C中生成一次范围内的随机数？

Question

C 编程新手，我正在尝试生成一个随机数一次。但当程序符合要求时，它会在用户指定的范围内生成 30 个随机数。使用数组会更容易吗？任何帮助都会很好。

编辑

程序应提示用户输入要模拟的销售数量(范围为 1 到 10000)。接下来，它应对每个模拟销售执行以下操作:选择一名随机员工来记入销售，随机确定销售的总金额，将该金额添加到所选员工的运行销售总额中，并增加该员工的销售数量。 - 这基本上就是我想要做的。抱歉造成困惑

#include<stdio.h>
#include<time.h>
#include<stdlib.h>

int main (void)
{
    int n,c; // n is the number of sales to simulate, c is the counter
    int id[30];// id[30] is the number of employees 
    srand(time(NULL));
    int myVar;

    printf("Enter the number of sales to simulate: ");
    scanf("%d", &n);
    while(n<1 || n>10000)//blocking while loop
    {
        //prompt user to enter proper number for calculation
        printf("Error: Enter a proper number in the range from 1 to 10000: \a");
        scanf("%d",&n);
    }
    printf("Id\n");//prints out the id
    for (c = 0; c<30; c++)
    {
        id[c] = c;
        printf("%d: ",id[c]); //prints out the id numbers starting from 0 and ending at 29
        myVar = rand() % n + 1;//prints random number sale ranging from 1 to n for each employee but needs to print once for a random employee ranging from 1 to n. And should print zeros for the rest of the employees. 
        printf("\t%d\n", myVar);
    }

    return 0;
}

Answer 1

随机数生成的代码位于运行 31 次的循环内。

for (c = 0; c<=30; c++)   //c = 0 to 31 -> runs 31 times
{
  myVar = rand() % n + 1;
  printf("%d\n", myVar);
}

如果您希望随机数仅生成一次，请删除 for 循环。