c - while 循环不会停止循环

Question

我想我搞砸了，我的代码过度循环(它不会停止)。即使输入0后它也会继续循环。请指出我哪里做错了。

#include <stdio.h>

int main()
{
    int day=1, exp=1, tallow;
    float allow,tday,daily, texpen;

    printf("\nDay %d allowance. [Type -1 to stop] --> ", day);
    scanf("%f", &allow);

    while(allow != -1){
        printf("-- Expenses %d [type 0 to stop]  ", exp);
        scanf("%f", &daily);exp++;
        while(daily == 0){
            printf("\nDay %d allowance : %.2f", day, allow);
            tday += daily;
            printf("\nDay %d expenses  : %.2f", day, tday);
            break;
        }
    }

        printf("\nTotal allowance for %d days : %.2f", day, tallow);
        printf("\nTotal expenses for %d days : %.2f\n", day, texpen);

    getch();
    return 0;
}

当前输出:

Day 1 allowance. [Type -1 to stop] --> 20

-- Expenses 1 [type 0 to stop]  5

-- Expenses 2 [type 0 to stop]  3

-- Expenses 3 [type 0 to stop] 0

Day 1 allowance : 20.00

Day 1 expenses  : 8.00 -- Expenses 4 [type 0 to stop]

如何摆脱“费用 4”？/如何在输入 0 后停止循环？

Answer 1

您可以更改您的

    while(daily == 0){

到

    if(daily == 0){

所以休息；将退出循环

    while(allow != -1){

然后不再打印“费用 4”。

并且您还需要将允许定义为 int，其中<​​/p>

scanf("%d", &allow);

应该是:

...
while(allow != -1){
    printf("-- Expenses %d [type 0 to stop]  ", exp);
    scanf("%f", &daily);exp++;
    tday += daily;
    if(daily == 0){
        printf("\nDay %d allowance : %.2f", day, allow);
        printf("\nDay %d expenses  : %.2f", day, tday);
        break;
    }
}