c - C 计数空间中的无限循环

Question

我正在编写一个程序来计算空格和元音，但它不起作用，我想我做了一个无限循环。我将向您展示我的代码:

int contar_p(char a[100]) {
    int i = 0, spaces = 1;

    while (a[i] != '\0' && i < 100) {
        if (a[i] == ' ') {
            spaces += 1;
            i++;
        }           

    }
    return spaces;
}

int contar_v(char b[100]) {
    int i = 0, counter = 0;

    while (b[i] != '\0' && i < 100) {
        if (b[i] == 'a' || b[i] == 'e' || b[i] == 'i' || b[i] == 'o' || b[i] == 'u') {
            counter += 1;
        }
        i++;
    }
    return counter;
}

int main(void){
    char phrase[100];
    int words = 0, vowels = 0;

    printf("write a phrase ");
    gets(phrase);

    palabras = contar_p(phrase);
    vocales = contar_v(phrase);

    printf("%d\n", words);
    printf("%d", vowels);

    return 0;
}

Answer 1

循环

while (a[i]!='\0'&&i<100){
    if(a[i]==' '){
        spaces+=1;
        i++;
    }           
}

是一个无限循环。将 i++ 放在 if 之外。将其更改为

while (a[i]!='\0'){  // No need of condition i < 100
    if(a[i]==' '){
        spaces+=1;
    }   
    i++;        
}