C Linux 你如何将参数传递给另一个程序？

Question

我想用 C 创建另一个进程。但我不知道如何将论点传递给另一个人，使用fork()、exec()这是我的代码

sls.c

   int main() {
    void start_game (const char* file_name,int N,int max_lives)
{
    pid_t pid;
    int child_status;
    pid = fork();

    if(pid!=0){
        wait(&child_status);
    }
    else{
       if(-1 == execl("./player","player",&file_name,&max_lives,(char *)NULL))
       {
       perror("execlp() failed");
       return 1;
       }
    }
  int r = 1+rand()%max_lives;
}
    return(0);
}

我需要将 file_name 和 ma​​x_live 传递给 player.c所以player.c可以读取同一个文件

player.c

int main(int argc,char *argv[]) {

pid_t child_pid = fork();
int child_status;
int sidekick_amount = (int)getpid%5;

void read_ints (const char* file_name)
{
 // Normal read file stuff here 
}


if (child_pid!=0)
{
    wait(&child_status);
}
else
{
    execlp("","-l",NULL);
    printf("Exec error\n");
    exit(-1);
}

   int lives = argv[2];
   printf("\nAt pos 0: Player %d has %d lives , %d sidekicks and 
   \n is ready to start ",(int)getppid(),lives,sidekick_amount);

    read_ints(file_name);
    return (0);
}

阅读文件并设置助手数量后。player.c需要为sidekick_amount生成sidekick.c进程作为 player.c 子元素。但我无法从 player.c 中获取 file_name 和 lives

sidekicks.c

enter code here

输出

At pos 0: Player 25477 has -5703328 lives , 1 sidekicks and is ready to start 

感谢您的所有帮助，非常感谢所有答案

Answer 1

您需要将整数 max_lives 转换为字符串，以便可以将其作为函数参数传递。当您传递文件名时，只需传递字符串本身，而不是指针的地址。

void start_game (const char* file_name,int N,int max_lives)
{
    pid_t pid;
    int child_status;
    pid = fork();


    if(pid!=0){
        wait(&child_status);
    }
    else{
        char max_lives_str[20];
        sprintf(max_lives_str, "%d", max_lives);
        if(-1 == execl("./player","player", file_name, max_lives_str, (char *)NULL))
        {
           perror("execlp() failed");
           return 1;
        }
    }
    int r = 1+rand()%max_lives;
}