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c - 我如何释放一个结构?

转载 作者:行者123 更新时间:2023-11-30 19:11:22 25 4
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我有一个 main 函数,它接收一个文件并将文件中的数字添加到矩阵中。我一切正常,它打印出正确的答案,但在 valgrind 中我遇到了泄漏,我肯定知道它,因为我没有在循环中释放 MatC: else if (numOfMatrices > 2)。前面带有箭头的行是需要释放的行。

主要功能如下:

#define _GNU_SOURCE
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "mmult.h"

int main(int argc, char* argv[]){
(void) argc;
FILE* fp = fopen(argv[0], "r");
char *firstLine = NULL;
char *ptr;
if (!fp){
fprintf(stderr, "Can't Open File");
return EXIT_FAILURE;
} else{ // Gets the number of matrices
char *buf = NULL;
size_t len = 100;
while (getline(&buf, &len, stdin)){
char *pch;
pch = strtok(buf, " \n");
firstLine = buf;
(void) pch;
break;
}
}

int numOfMatrices = strtod(firstLine, &ptr);
free(firstLine);

// Gets the number of rows and columns of the matrix
for (int m = 0; m < numOfMatrices; m++){
int x, y, i, j;
Matrices MatA;
Matrices MatB;
Matrices MatC;
Matrices MatD;
if (numOfMatrices == 1){
MatA.Matrix = mread(stdin, &x, &y);
MatA.row = x;
MatA.col = y;

printf("%d %d\n", MatA.row, MatA.col);
mwrite(stdout, MatA.row, MatA.col, MatA.Matrix);
xfree(MatA.row, MatA.col, MatA.Matrix);
} else if (numOfMatrices >= 2){
if (numOfMatrices == 2){
if (m == 0){
MatA.Matrix = mread(stdin, &x, &y);
MatA.row = x;
MatA.col = y;

MatB.Matrix = mread(stdin, &i, &j);
MatB.row = i;
MatB.col = j;

MatC.Matrix = mmult(MatA.row, MatA.col, MatA.Matrix, MatB.row, MatB.col, MatB.Matrix);
MatC.row = MatA.row;
MatC.col = MatB.col;

xfree(MatA.row, MatA.col, MatA.Matrix);
xfree(MatB.row, MatB.col, MatB.Matrix);
printf("%d %d\n", MatC.row, MatC.col);
mwrite(stdout, MatC.row, MatC.col, MatC.Matrix);
xfree(MatC.row, MatC.col, MatC.Matrix);
}
} else if (numOfMatrices > 2){
if (m == 0){
MatA.Matrix = mread(stdin, &x, &y);
MatA.row = x;
MatA.col = y;

MatB.Matrix = mread(stdin, &i, &j);
MatB.row = i;
MatB.col = j;

-> MatC.Matrix = mmult(MatA.row, MatA.col, MatA.Matrix, MatB.row, MatB.col, MatB.Matrix);
MatC.row = MatA.row;
MatC.col = MatB.col;

xfree(MatA.row, MatA.col, MatA.Matrix);
xfree(MatB.row, MatB.col, MatB.Matrix);

for (int x = 2; x < numOfMatrices; x++){
MatD.Matrix = mread(stdin, &i, &j);
MatD.row = i;
MatD.col = j;

-> MatC.Matrix = mmult(MatC.row, MatC.col, MatC.Matrix, MatD.row, MatD.col, MatD.Matrix);

xfree(MatD.row, MatD.col, MatD.Matrix);
if (x == (numOfMatrices-1)){
printf("%d %d\n", MatC.row, MatC.col);
mwrite(stdout, MatC.row, MatC.col, MatC.Matrix);
xfree(MatC.row, MatC.col, MatC.Matrix);
}

}
}
}
}
}
fclose(fp);
}

此外,这是我的 xfree 函数,free 是一个矩阵:

// Free all memory allocated for A 
void xfree(int r, int c, double **A){
(void) c;
for (int y = 0; y < r; y++){
free(A[y]);
}
free(A);
}

我还为矩阵创建了一个结构:

typedef struct Matrices{
double **Matrix; // The matrix held in this node
int row; // Number of rows in the Matrix
int col; // Number of Columns in the Matrix
} Matrices;

Valgrind 输出:

ShaolinGOD@comp:~/Desktop/Project2$ valgrind --leak-check=full --show-leak-kinds=all --track-origins=yes ./mmult < OneMatrix.txt
==7984== Memcheck, a memory error detector
==7984== Copyright (C) 2002-2015, and GNU GPL'd, by Julian Seward et al.
==7984== Using Valgrind-3.11.0 and LibVEX; rerun with -h for copyright info
==7984== Command: ./mmult
==7984==
2 2
52.00 52.00
80.00 80.00
==7984==
==7984== HEAP SUMMARY:
==7984== in use at exit: 144 bytes in 9 blocks
==7984== total heap usage: 30 allocs, 21 frees, 133,624 bytes allocated
==7984==
==7984== 32 bytes in 2 blocks are indirectly lost in loss record 1 of 4
==7984== at 0x4C2DB8F: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==7984== by 0x400D11: xalloc (mmult.c:83)
==7984== by 0x400BF7: mmult (mmult.c:65)
==7984== by 0x401111: main (mmult-driver.c:86)
==7984==
==7984== 48 (16 direct, 32 indirect) bytes in 1 blocks are definitely lost in loss record 2 of 4
==7984== at 0x4C2DB8F: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==7984== by 0x400CDE: xalloc (mmult.c:81)
==7984== by 0x400BF7: mmult (mmult.c:65)
==7984== by 0x401111: main (mmult-driver.c:86)
==7984==
==7984== 64 bytes in 4 blocks are indirectly lost in loss record 3 of 4
==7984== at 0x4C2DB8F: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==7984== by 0x400D11: xalloc (mmult.c:83)
==7984== by 0x400BF7: mmult (mmult.c:65)
==7984== by 0x4011A4: main (mmult-driver.c:98)
==7984==
==7984== 96 (32 direct, 64 indirect) bytes in 2 blocks are definitely lost in loss record 4 of 4
==7984== at 0x4C2DB8F: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==7984== by 0x400CDE: xalloc (mmult.c:81)
==7984== by 0x400BF7: mmult (mmult.c:65)
==7984== by 0x4011A4: main (mmult-driver.c:98)
==7984==
==7984== LEAK SUMMARY:
==7984== definitely lost: 48 bytes in 3 blocks
==7984== indirectly lost: 96 bytes in 6 blocks
==7984== possibly lost: 0 bytes in 0 blocks
==7984== still reachable: 0 bytes in 0 blocks
==7984== suppressed: 0 bytes in 0 blocks
==7984==
==7984== For counts of detected and suppressed errors, rerun with: -v
==7984== ERROR SUMMARY: 2 errors from 2 contexts (suppressed: 0 from 0)
ShaolinGOD@comp:~/Desktop/Project2$

最佳答案

xfree 功能没问题。问题是 xfree 并未针对 MatC.Matrix

的所有分配调用

您似乎正在尝试转换MatC.Matrix。为此,您可以分配一个临时矩阵,将旧矩阵复制到临时矩阵,释放旧矩阵,然后将旧矩阵指针设置为临时矩阵。

例如,更改以下部分:

MatC.Matrix = mmult(MatA.row, MatA.col, MatA.Matrix, MatB.row, MatB.col, MatB.Matrix);
MatC.row = MatA.row;
MatC.col = MatB.col;

xfree(MatA.row, MatA.col, MatA.Matrix);
xfree(MatB.row, MatB.col, MatB.Matrix);

for (int x = 2; x < numOfMatrices; x++)
{
MatD.Matrix = mread(stdin, &i, &j);
MatD.row = i;
MatD.col = j;

MatC.Matrix = mmult(MatC.row, MatC.col, MatC.Matrix, MatD.row, MatD.col, MatD.Matrix);
xfree(MatD.row, MatD.col, MatD.Matrix);

if (x == (numOfMatrices - 1))
{
printf("%d %d\n", MatC.row, MatC.col);
mwrite(stdout, MatC.row, MatC.col, MatC.Matrix);
xfree(MatC.row, MatC.col, MatC.Matrix);
}
}

对此:

MatC.Matrix = mmult(MatA.row, MatA.col, MatA.Matrix, MatB.row, MatB.col, MatB.Matrix);
MatC.row = MatA.row;
MatC.col = MatB.col;

xfree(MatA.row, MatA.col, MatA.Matrix);
xfree(MatB.row, MatB.col, MatB.Matrix);

for (int x = 2; x < numOfMatrices; x++)
{
MatD.Matrix = mread(stdin, &i, &j);
MatD.row = i;
MatD.col = j;

Matrices temp;
temp.Matrix = mmult(MatC.row, MatC.col, MatC.Matrix, MatD.row, MatD.col, MatD.Matrix);
xfree(MatD.row, MatD.col, MatD.Matrix);

//free MatC.Matrix
xfree(MatC.row, MatC.col, MatC.Matrix);

//copy pointers from temp to MatC.Matrix
MatC.Matrix = temp.Matrix;
for (int k = 0; k < temp.row; k++)
MatC.Matrix[k] = temp.Matrix[k];
MatC.row = temp.row;//<== added (EDIT ***********)
MatC.col = temp.col;//<== added (EDIT ***********)

if (x == (numOfMatrices - 1))
{
printf("%d %d\n", MatC.row, MatC.col);
mwrite(stdout, MatC.row, MatC.col, MatC.Matrix);
}
}

//add xfree here:
xfree(MatC.row, MatC.col, MatC.Matrix);

现在分配数量和 xfree 应该匹配。

关于c - 我如何释放一个结构?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40275274/

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