c - 获取进程返回-1073741819 (0xC0000005)错误而不是答案

Question

当我尝试获取答案时，出现以下错误: 进程返回“-1073741819 (0xC0000005)”。我的目标很简单:我从用户那里获取 4 个数字，1 个用于菜单，另外 3 个用于进行数学运算，但我无法得到答案:它卡住了。

我的代码:

#include <stdio.h>
#include <stdlib.h>
int main()
{
    int menu,t1,t2,sonuc1;
    double r1,sonuc,sonuc2;
    printf("\t*************Menu*****************\n");
    printf("\n");
    printf("1.\t SADECE TAM SAYILARI TOPLA\n");
    printf("2.\t TAM SAYILARI TOPLA REEL SAYI ILE CARP\n");
    printf("3.\t REEL SAYININ KARESİNİ ALARAK 1.TAM SAYI İLE ÇARP\n");
    printf("4.\t CIKIS\n");
    printf("Seciniz:");
    scanf("%d",&menu);
    if(menu == 4){
        printf("Hoscakal");
        return 0;
    }
    else if (menu !=1 && menu !=2 && menu !=3){
        printf("Gecersiz Deger!");
        return 0;
    }
    printf("\nBirinci tam sayiyi giriniz: ");
    scanf("%d",&t1);
    printf("\nIkinci tam sayiyi giriniz: ");
    scanf("%d",&t2);
    if (t2==0){
            t2 = 1;
        }
    printf("\nReel sayiyi giriniz: ");
    scanf("%lf",r1);
    if(r1>0 || r1 == 0){
        r1 = -1;
    }
    if(menu == 1){
            sonuc1 = (t1+t2);
    printf("Sonuc: %d",sonuc1);
    }
    else if(menu == 2) {
            sonuc = (t1+t2)*r1;
        printf("Sonuc: %lf",sonuc);
    }
    else if(menu == 3) {
            sonuc2 = (r1*r1)*t1;
        printf("Sonuc: %lf",sonuc2);
    }
}

输出:output

Answer 1

scanf("%lf",r1);

scanf 的 %lf 格式说明符需要一个 double *，但您传入的是一个 double >。格式说明符和给定参数之间的不匹配会调用 undefined behavior ，在这种情况下会导致崩溃。

将其更改为:

scanf("%lf",&r1);