c - 第34行获取被调用对象不是函数或函数指针问题:13

Question

因此，当我编译代码时，我收到一条错误消息:

called object is not a function pointer on line 34:13

我做错了什么？

#include <stdio.h>
#include <math.h>

int calendar(int q,int m,int k,int j);

int main(){
    char days[8][100] = {"Saturday","Sunday","Monday","Tuesday","Wednesday","Thursday","Friday"};
    int q,m,k,j,year,day_num;
    printf("What day of the month is it? e.g. 31");
        scanf("%d", &q);
    printf("What month is it? e.g. January = 1, February = 2");
        scanf("%d", &m);
    printf("What year is it?");
        scanf("%d", &year);
    if(m == 1){
        m = 13;
        year--;
    }
    if(m == 2){
        m = 14;
        year--;
    }
    k = year%100;
    j = year/100;

    day_num = calendar(q,m,k,j);

    printf("The day for the selected date is %s", days[day_num]);
}

calendar() 函数定义为:

int calendar(int q,int m,int k,int j){
    int day;

    day = (q+(13(m+1)/5)+k+(k/4)+(j/4)+(5*j)) % 7; // Problem is here

    return day;
}

Answer 1

问题可能是“13(m+1)”线上

day = (q+(13(m+1)/5)+k+(k/4)+(j/4)+(5*j)) % 7;

看起来你错过了一个“*”字符(或其他字符)。 13*(m+1) 应该可以解决您的问题。