有人能告诉我我的错误在哪里吗？我的程序给出了错误的输出

Question

/*3。编写一个程序来计算 10 名员工的净工资。使用函数执行以下任务:-A。读入 10 名员工的总工资。b.计算每个员工的净工资。C。以表格形式显示每个员工的总工资和净工资。例如:-

工资总额 工资 Netty 2000 18203000 2720*/

//计算10名员工的净工资并显示

#include<stdio.h>

int readSalary();
int Calculatenet(int);
void displaysalary(int,int);

int main()
{

int i,salary[10],netsalary[10] ;

         for(i=0;i<10;i++)
          {

             salary[i]=readSalary(); /*for each and every element in the array, the value is entered*/

             netsalary[i]=Calculatenet(salary[i]); /*the value is passed into the function*/

             displaysalary=(salary[i],netsalary[i]); /*to display the results, the values frm both function are passed in*/
           } /*A bit confused about passing in arrays in this form. Pls correct me.*/ 

       return 0;
 }

int readSalary()
{
    int salary;
    printf("Enter your gross salary:");
    scanf("%d",&salary);
    return salary;

 }

int Calculatenet(int pay)
{
    int netsalary;
    netsalary= pay-(pay*0.1);//formula to calculate the net salary
    return netsalary;
}

 void displaysalary(int pay_, int netsalary_)
 {
    printf("Gross salary\t Net Salary\n");
    printf("%d\t %d\n",pay_,netsalary_);
}

Answer 1

打开警告:

error: lvalue required as left operand of assignment

问题是您正在尝试为函数赋值。

改变

displaysalary = (salary[i],netsalary[i]);

至

displaysalary(salary[i],netsalary[i]);

另一方面(正如 Tim Seguine 所指出的)你正在混合整数和 float

int netsalary;
netsalary= pay-(pay*0.1);//formula to calculate the net salary

更改为

netsalary= pay-(pay/10);//formula to calculate the net salary