c - 我没有正确处理多个 block

Question

我有一个作业，我需要读取输入行，例如

2
67 5 100 1 11 97 98 10 1 110
15 72 10 101 47 67 88 20 94 6 22 11

4
61 11 93 4 73 39 78 34 17 104
23 43 11 93 65 52 20 96 66 31 86 24 40 61 102 13 50 51
73 43 28 73 8 89 31 68 77 27 24 77 42 72 15 24 64 51
25 75 7 90 10 111 17 16

......

处理每两个整数( block 中的第一行仅告诉我们将处理多少个单词)，将它们相加然后匹配将它们转换为相应的 ASCII 字符。上面的例子是两个 block 。输出应该是:

 Decoded messages:
 Hello World!
 Happy Bhutanese teacher's day!

在处理具有多个 block (超过 20 个 block 等)且在一个输入文本上遵循相同格式的文件时，我遇到了问题。我可以很好地处理一个 block ，也可以处理两个 block ，但不能很好，因为我的程序似乎没有结束。每行长度不得超过 256 个字符。 numOfPuzzl 指的是我们每个 block 处理的单词数量。我非常感谢任何帮助。我附上了我的代码并尽可能多地发表了评论。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char* argv[])
{
    //user will type in file name they choose to process and we allocated  in filename[]
    char filename[256];
    printf("Enter filename: ");
    scanf("%s", filename);

    //process filename username typed in
    FILE *pFile;
    pFile = fopen(filename, "r");

    //if there's nothong to read
    if (pFile == NULL){
        exit(1);
    }

    printf("Decoded messages:\n");

    //create array we will putting lines into
    char myString[256];
    //simply gets the first line, which is always a lone integer
    fgets(myString, 256, pFile);

    int numOfPuzzl;
    sscanf(myString, "%d", &numOfPuzzl);
    //printf("puzzles to solve: %d\n", numOfPuzzl);
    int wordsProcessed = 0;

    //just remember that myString has entire line

    //start processing the lines that follow, a line is a word
    while (fgets(myString, 256, pFile) != NULL){
        int num = 0; //first integer in line
        int secondNum = 0;  //second int. in line
        int tot = 0;  //how many bytes
        int bytes_read = 0; //bytes processed

        char *endOfStrAdr = strchr(myString, '\0');  //returns address of end terminating char.
        int endOfStrIdx = endOfStrAdr - myString;  //this will give me the index of where the terminating char. occurs within my array

        //start scanning integers within array making sure to not sccan out of bounds
        while (tot < endOfStrIdx){

            //first integer allocated as well as how many byes it was
            sscanf(myString + tot, "%d %n", &num, &bytes_read);

            tot += bytes_read;  //keeps tab so we don't have to read from the begn. of array everytime

            //second integer allocated as well as how many byes it was

            sscanf(myString + tot, "%d %n", &secondNum, &bytes_read);

            tot += bytes_read;   ////keeps tab so we don't have to read from the begn. of array everytime

            printf("%c", (char) num + secondNum); //add the two integers and cast them to char

            //we want to check if we are the end of the string, our word
            if (tot ==  endOfStrIdx){

                printf(" ");
                wordsProcessed++;
                //we want to print a new line char. if we finished processing all the words for the puzzle
                if (wordsProcessed == numOfPuzzl){
                    printf("\n");
                    fgets(myString, 256, pFile);
                }
            }
        }
    }
    fclose(pFile);
}

Answer 1

• 忽略拼图之间的空行。
• 在处理新谜题之前重置参数(numOfPuzzl 和 wordsProcessed)。

要存档它，请更改

if (wordsProcessed == numOfPuzzl) {
    printf("\n");
    fgets(myString, 256, pFile);
}

进入

if (wordsProcessed == numOfPuzzl) {
    printf("\n");
    while ( fgets(myString, 256, pFile) != NULL ){
        if ( sscanf(myString, "%d", &numOfPuzzl) == 1 )
            break;
    }
    wordsProcessed = 0;
}