php - JSON 错误 : parsererror

Question

我正在为我的社交网络开发气球通知。当有 2 个或更多通知时，我遇到了这个错误。我在 jsonlint.com 上检查了我的 JSON 响应，我在第 6 行出错。

JSON 响应:

    {
    "nid": "1101",
    "img": "<img src=\".\/images\/icons\/he_wall_post_icon.png\">",
    "notifier": "Sarah O&#039;conner",
    "url": " has commened on your <a href=\"wall_action.php?id=1463\">post<\/a>"
}{
    "nid": "1100",
    "img": "<img src=\".\/images\/icons\/he_wall_post_icon.png\">",
    "notifier": "Sarah O&#039;conner",
    "url": " likes your <a href=\"wall_action.php?id=1463\">post<\/a>"
}

这是我的 PHP 部分:

$ret_arr = array('nid' => $nid2,'img' => $img, 'notifier' => $notifier, 'url' => $url);

echo json_encode($ret_arr);

这是我的 JS 部分:

    function noob()
{
    jQuery.ajax({
        url: 'notifications.php?n=1',
        dataType: 'json',
        success: function(data){
            alert('Success!');
        },
        error: function(requeset, textStatus, errorThrown){
            alert('error:'+textStatus);
        }
    });
}

我怎样才能完成它!

谢谢大家。

Answer 1

您的 JSON 缺少列表括号和对象之间的逗号。

它应该是这样的:

[
  {
    "nid": "1101",
    "img": "<img src=\".\/images\/icons\/he_wall_post_icon.png\">",
    "notifier": "Sarah O&#039;conner",
    "url": " has commened on your <a href=\"wall_action.php?id=1463\">post<\/a>"
  },
  {
    "nid": "1100",
    "img": "<img src=\".\/images\/icons\/he_wall_post_icon.png\">",
    "notifier": "Sarah O&#039;conner",
    "url": " likes your <a href=\"wall_action.php?id=1463\">post<\/a>"
  }
]