c - 警告 : passing argument 1 of ‘uart1_sendchar’ makes pointer from integer without a cast [enabled by default]

Question

我收到警告，但我尝试从类似的帖子中获取信息，但没有得到满意的结果printstring 获取 unsigned char 并发送 char take *char 那么我是否必须输入强制类型转换或其他内容？请帮忙

uartcustom.c: In function ‘uart1_printString’:
uartcustom.c:162:9: warning: passing argument 1 of ‘uart1_sendchar’ makes pointer
                             from integer without a cast [enabled by default]
uart1_sendchar(string[local_counter]); // print each character
     ^

使用的两个函数是串口1_发送字符和 uart1_printstring

/*****************************************************************************   
 //     Uart 1 send char                         */ 
 /***************************************************************************/
void uart1_sendchar(char* tempchar)
{
    int temp;
    temp=write(device_uart1,&tempchar,1);
    if(temp < 0) 
    {
        printf("port failed to write\n");
    }
}



/*****************************************************************************   
//      Uart 1 printstring                       */ 
/*****************************************************************************/

void uart1_printString( unsigned char *string)
{
    int local_counter = 0;
    // loop through until reach string's zero terminator
    while (string[local_counter] != 0)
    {
        uart1_sendchar(string[local_counter]); // print each character
        local_counter++;
    }
}

Answer 1

string 是 unsigned char *，因此 string[local_counter] 是 unsigned char

您可能想要:

uart1_sendchar(&string[local_counter]);