C - 链表插入

Question

我想创建 5 个节点并在第三个和第四个节点之间插入一个新节点。这是代码。当我运行它时，我没有收到错误或输出。我做错了什么？提前致谢。

#include <stdio.h>
#include <stdlib.h>

typedef struct node{

                int data;
                struct node *next;

}node;


int main(void) {

                struct node *root, *newElement, *temp;

                // first node is created.
                root = (node*)malloc(sizeof(node));
                root->data = 11;

                // to create 4 nodes more after the first one is created.
                int i;
                for (i=0; i <= 3; i++){

                               root->next = (node*)malloc(sizeof(node));
                               root = root->next;
                               root->data = (i * 10);

                }

                // new node to insert.
                newElement = (node*)malloc(sizeof(node));
                newElement-> data = 1;



                temp = (node*)malloc(sizeof(node));

                temp = root->next->next;

                root->next -> next = newElement;

                newElement->next = temp;


                // print the values 
                int j;
                for(j=0; j<=4; j++){
                    root = root->next;
                    printf("%d\n", root->data);
                }


                return 0;

}

Answer 1

root = temp = (node*)malloc(sizeof(node));//no need cast from void*
temp->data = 11;

int i;
for (i=0; i <= 3; i++){
    //don't change root
    temp->next = (node*)malloc(sizeof(node));
    temp = temp->next;
    temp->data = (i * 10);
}
temp->next = NULL;//next of last node need set to NULL 

newElement = (node*)malloc(sizeof(node));
newElement-> data = 1;

//temp = (node*)malloc(sizeof(node));//no need (this make memory leak)
temp = root->next->next;
root->next->next = newElement;
newElement->next = temp;


for(temp = root; temp; temp = temp->next){
    printf("%d\n", temp->data);
}