c - 为什么我在 C 程序中收到杂散 '342' 错误？

Question

这个问题已经有答案了:

Stray '\342' in C++ program [duplicate] (4 个回答)

已关闭 6 年前。

我试图在 GNU/Linux 操作系统中编译 C 文件，但是当我尝试编译此代码时，编译器给出了一些错误。

我的op.c文件是这样的:

#include <stdio.h>

int main(int argc, char *argv[]){

    int i;
    for (i=0; i < argc; i++){
        printf(“command line argument [%d] = %s \n”, i, argv[i]);
    }

    return 0;
}

当我尝试编译此代码时，出现这些错误。我该如何修复它们？

op.c: In function ‘main’:
op.c:6:3: error: stray ‘\342’ in program
   printf(“command line argument [%d] = %s \n”, i, argv[i]);
   ^
op.c:6:3: error: stray ‘\200’ in program
op.c:6:3: error: stray ‘\234’ in program
op.c:6:13: error: ‘command’ undeclared (first use in this function)
   printf(“command line argument [%d] = %s \n”, i, argv[i]);
             ^
op.c:6:13: note: each undeclared identifier is reported only once for each function it appears in
op.c:6:21: error: expected ‘)’ before ‘line’
   printf(“command line argument [%d] = %s \n”, i, argv[i]);
                     ^
op.c:6:21: error: stray ‘\’ in program
op.c:6:21: error: stray ‘\342’ in program
op.c:6:21: error: stray ‘\200’ in program
op.c:6:21: error: stray ‘\235’ in program

Answer 1

在 C 中使用正确的引号表示字符串。

printf("command line argument [%d] = %s \n", i, argv[i]);

而不是

printf(“command line argument [%d] = %s \n”, i, argv[i]);