数一下总数文件中的关键字

Question

我想统计总数。文件中的关键字，但代码对用于声明变量的关键字进行计数。

void main()
{
 //2d array used to store the keywords but few of them are used.

     char key[32][12]={"int","char","while","for","if","else"};

//cnt is used to count the occurrence of the keyword in the file. 

     int cnt=0,i;

 //used to store the string that is read line by line.

     char ch[100];

 FILE *fp=fopen("key.c","r");

 //to check whether file exists or not

    if(fp=='\0') 
    {
     printf("file not found..\n");
     exit(0);
     }
  //to extract the word till it don't reach the end of file 

    while((fscanf(fp,"%s",ch))!=EOF)
   {
    //compare the keyword with the word present in the file.

      for(i=0;i<32;i++)
      {
  // compare the keyword with the string in ch.

       if(strcmp(key[i],ch)==0) {

 //just to check which keyword is printed.
       printf("\nkeyword is : %s",ch); 
       cnt++;
      }
     }
  }
    printf("\n Total no. of keywords are : %d", cnt);
    fclose(fp);
}

预期输出应该是:

   Total no. of keywords are : 7

实际输出即将到来:

   Total no. of keywords are : 3

Answer 1

fscanf(fp,"%s",ch) 将匹配一系列非空白字符(请参阅 cpp reference )，因此在您的情况下 for， while 和 if 不会作为单个单词进行匹配 - 因为它们后面没有空格。