c - 程序无法成功运行？段错误 11、表达式被视为空指针； C

Question

运行程序时出现段错误，编译程序时出现这些错误。我必须做什么才能让我的程序运行。

./documents/TEST/TEST/main.c:117:72: warning: expression which evaluates to zero
          treated as a null pointer constant of type 'const char *'
          [-Wnon-literal-null-conversion]
                strcpy(dragon_index->team[dragon_index->num_dragons].name, '\0');
                                                                           ^~~~
    /usr/include/secure/_string.h:83:33: note: expanded from macro 'strcpy'
      __builtin___strcpy_chk (dest, src, __darwin_obsz (dest))
                                    ^
    ./documents/TEST/TEST/main.c:121:73: warning: expression which evaluates to zero
          treated as a null pointer constant of type 'const char *'
          [-Wnon-literal-null-conversion]
                strcpy(dragon_index->team[dragon_index->num_dragons].color, '\0');
                                                                            ^~~~
    /usr/include/secure/_string.h:83:33: note: expanded from macro 'strcpy'
      __builtin___strcpy_chk (dest, src, __darwin_obsz (dest))

Answer 1

您正在将 '\0'(其类型为 char，值为 0)传递给 strcpy，strcpy 需要 const char* 类型的参数作为第二个参数。回想一下，“\0”和“\0”不同。