将代码更改为没有指针

Question

我不想想要指针，如何在不使用指针的情况下编写这2个函数，以及对函数的调用将如何改变？

void addSubString(char subString[], char help[], int *position, int until){
    int counter = 0;
    for (; counter< until; counter++, (*position)++){
        help[*position] = subString[counter];
    }
}

void addReplaceWith(char replaceWith[], char help[], int *position){
    int counter = 0;
    for (; replaceWith[counter] != '\0'; counter++, (*position)++){
        help[*position] = replaceWith[counter];
    }
}

通话:

addReplaceWith(replaceWith, help, &helpCounter)
addSubString(subString, help, &helpCounter, subStringHelp); 

Answer 1

怎么样:

int addSubString(char subString[], char help[], int position, int until){
    int counter = 0;
    for (; counter< until; counter++, position++){
        help[position] = subString[counter];
    }
    return position;
}

int addReplaceWith(char replaceWith[], char help[], int position){
    int counter = 0;
    for (; replaceWith[counter] != '\0'; counter++, position++){
        help[position] = replaceWith[counter];
    }
    return position;
}

通话:

helpCounter = addReplaceWith(replaceWith, help, helpCounter)
helpCounter = addSubString(subString, help, helpCounter);

我认为“substringHelp”部分是一个拼写错误？