javascript - 正则表达式将字符串拆分为单独的键

Question

我正在做一个有趣的项目，但我在为此编写正则表达式时遇到了一些麻烦。

使用正则表达式和 Javascript，我想将我的输入字符串拆分为一个“键”数组。具有无效键的字符串应返回 0 个键(null、空数组，随便什么都可以)。

“规范”

<input string>      => <matches>

# named keys
a                   => ['a']
b                   => ['b']
foo[bar]            => ['foo', 'bar']

# numeric keys are ok too
a[0]                => ['a', '0']
b[1]                => ['b', '1']

# 'push' syntax is also valid
push[]              => ['push', '']
hello[]             => ['hello', '']

# complex!
complex[named][0][] => ['complex', 'named', '0', '']

无效示例

# named keys must start with [a-zA-Z]
_invalid            => null
3foo[abc]           => null

# named keys can include a number as long as they start with a letter
foo3valid[this_is_valid_2] => ['foo3valid', 'this_is_valid_2']

到目前为止我有什么

var regex = /^(?:\[?([a-zA-Z][a-zA-Z0-9_]*|[a-zA-Z0-9_]*)\]?)+$/g;
var keys = [];

myInput.replace(regex, function(match,capture,pos,source){
    keys.push(capture);
});

console.log(myInput, keys);

它是如何失败的

我的正则表达式只匹配最后一个“键”例如，

# should be ['a', 'b', 'c']
a[b][c]   => ['c']

jsFiddle 修补

jsfiddle

Answer 1

我采用了另一种方法来获得预期的结果:

1. 测试给定的短语是否有效。
2. 如果有效，使用全局匹配创建一个数组。

代码: fiddle :http://jsfiddle.net/MVJZc/2/

///Example
var myInput = "a[b][][c]";

var validate = /^[a-zA-Z][a-zA-Z0-9_]*(?:\[(?:\d*|[a-zA-Z0-9_]+)\])*$/,
    pattern = /[a-zA-Z0-9_]+|(?=\[\])/g,
    //(?=\[\]) is used to create an empty entry for []
    keys = null;
if (validate.test(myInput)) {
    keys = myInput.match(pattern);
}

注意:如果你想扩展模式，例如要包含 $ 字符，请修改第一个 RegEx。第二个 RegEx (pattern) 应至少包含所有有效字符。