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需要 C 标识符吗?

转载 作者:行者123 更新时间:2023-11-30 18:32:45 24 4
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我正在开发一个迷宫游戏,所以我查找了一些迷宫生成代码并发现了这个 http://en.wikipedia.org/wiki/User:Purpy_Pupple/Maze首先,我得到 Expected ',',一旦我在该行添加 , ,它就会给我“Mze.c:33: 预期标识符”

这是我的修改版本(仅修复错误)我刚刚开始学习C。

//Purpy Pupple's amazing maze generator. 
//Released under the CC-BY-SA 3.0 License and the GFDL
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define UP 0 //-y
#define DOWN 1 //+y
#define LEFT 2 //-x
#define RIGHT 3 //+x
#define OUTFILE "MAZE"
#define WHITE fprintf(outfile, "%c%c%c", 255,255,255)
#define BLACK fprintf(outfile, "%c%c%c", 0,0,0)
#define RED fprintf(outfile, "%c%c%c", 0,0,255)

//#define nodeadend//generate a maze without any dead ends! (consequently, many solutions to maze)
#define prim //enable this to generate mazes using prim's algorithm.
#define backtrack//enable this to generate mazes using depth-first search. Don't enable both.
//#define movie //this option spams bitmaps to illustrate each step of generation.

long numin=1; //Number of cells in the maze.
const int xsize=152;
const int ysize=122;

void initialize();
void generate();
void savebmp(int xspecial, int yspecial);


struct cell;

struct cell {
//I have no idea why it wanted the ',' there
,bool in, up, left;//Does the wall to the left of this cell exist?
int prevx, prevy; //The coordinates of the previous cell, used for backtracking.
};

cell MAZE[xsize][ysize];

int main(){
srand((unsigned int)time(NULL)); //seed random number generator with system time
initialize(); //initialize the maze
generate(); //generate the maze
#ifdef movie
for(int i=1;i<10;i++){
numin++;
savebmp(0,0); //output the bitmap
}
#else movie
savebmp(0,0);
#endif
return 0;
}

void initialize(){
//Initialize the maze!
for(int x=0;x<xsize;x++){
for(int y=0;y<ysize;y++){
//The maze cells on the edges of the maze are "in" to provide padding. Otherwise, all maze cells are not in.
MAZE[x][y].in = (x==0||x==xsize-1||y==0||y==ysize-1)?1:0;
//All maze cells have all walls existing by default, except the perimeter cells.
MAZE[x][y].up = (x==0||x==xsize-1||y==0)?0:1;
MAZE[x][y].left = (x==0||y==0||y==ysize-1)?0:1;
}
}
return;
}

void generate(){
int xcur=1, ycur=1;//start growing from the corner. It could theoretically start growing from anywhere, doesn't matter.
MAZE[xcur][ycur].in = 1;
int whichway;
bool success;
do{
#ifdef movie
savebmp(xcur,ycur);
#endif
#ifdef nodeadend
if( MAZE[xcur][ycur-1].in&&MAZE[xcur][ycur+1].in&&
MAZE[xcur-1][ycur].in&&MAZE[xcur+1][ycur].in ){
//If at a dead end, randomly destroy a wall to make it not a dead end!
do{
success=0;
whichway=rand()%4;
switch(whichway){
case UP:
if(MAZE[xcur][ycur].up&&ycur!=1){
success=1;
MAZE[xcur][ycur].up=0;
}
break;
case DOWN:
if(MAZE[xcur][ycur+1].up&&ycur!=ysize-2){
success=1;
MAZE[xcur][ycur+1].up=0;
}
break;
case LEFT:
if(MAZE[xcur][ycur].left&&xcur!=1){
success=1;
MAZE[xcur][ycur].left=0;
}
break;
case RIGHT:
if(MAZE[xcur+1][ycur].left&&xcur!=xsize-2){
success=1;
MAZE[xcur+1][ycur].left=0;
}
break;
}
}while(!success);
}
#endif
#ifdef backtrack
while( MAZE[xcur][ycur-1].in&&MAZE[xcur][ycur+1].in&&
MAZE[xcur-1][ycur].in&&MAZE[xcur+1][ycur].in ){
//If all the neighbourhood cells are in, backtrack.
int xcur2=MAZE[xcur][ycur].prevx;
ycur=MAZE[xcur][ycur].prevy;
xcur=xcur2;
}
#endif
#ifdef prim
do{
//randomly find a cell that's in the maze
xcur=rand()%(xsize-2)+1;
ycur=rand()%(ysize-2)+1;
}while(!MAZE[xcur][ycur].in ||
MAZE[xcur][ycur-1].in&&MAZE[xcur][ycur+1].in&&
MAZE[xcur-1][ycur].in&&MAZE[xcur+1][ycur].in);
#endif
do{
//Randomly grow the maze if possible.
success=0;
whichway=rand()%4;
switch(whichway){
case UP:
if(!MAZE[xcur][ycur-1].in){
success=1;
MAZE[xcur][ycur].up=0;
MAZE[xcur][ycur-1].prevx=xcur;
MAZE[xcur][ycur-1].prevy=ycur;
ycur--;
}
break;
case DOWN:
if(!MAZE[xcur][ycur+1].in){
success=1;
MAZE[xcur][ycur+1].up=0;
MAZE[xcur][ycur+1].prevx=xcur;
MAZE[xcur][ycur+1].prevy=ycur;
ycur++;
}
break;
case LEFT:
if(!MAZE[xcur-1][ycur].in){
success=1;
MAZE[xcur][ycur].left=0;
MAZE[xcur-1][ycur].prevx=xcur;
MAZE[xcur-1][ycur].prevy=ycur;
xcur--;
}
break;
case RIGHT:
if(!MAZE[xcur+1][ycur].in){
success=1;
MAZE[xcur+1][ycur].left=0;
MAZE[xcur+1][ycur].prevx=xcur;
MAZE[xcur+1][ycur].prevy=ycur;
xcur++;
}
break;
}
}while(!success);
MAZE[xcur][ycur].in=1;
numin++; //Every iteration of this loop, one maze cell is added to the maze.
}while(numin<(xsize-2)*(ysize-2));
#ifdef movie
savebmp(xcur,ycur);
#endif
return;
}

void savebmp(int xspecial, int yspecial){
//save a bitmap file! the xspecial, yspecial pixel is coloured red.
FILE * outfile;
int extrabytes, paddedsize;
int x, y, n;
int width=(xsize-1)*2-1;
int height=(ysize-1)*2-1;

extrabytes = (4 - ((width * 3) % 4))%4;

char filename[200];

sprintf(filename, "%s_%dx%d_n%d.bmp", OUTFILE, xsize, ysize, numin);
paddedsize = ((width * 3) + extrabytes) * height;

unsigned int headers[13] = {paddedsize + 54, 0, 54, 40, width, height, 0, 0, paddedsize, 0, 0, 0, 0};

outfile = fopen(filename, "wb");
fprintf(outfile, "BM");

for (n = 0; n <= 5; n++){
fprintf(outfile, "%c", headers[n] & 0x000000FF);
fprintf(outfile, "%c", (headers[n] & 0x0000FF00) >> 8);
fprintf(outfile, "%c", (headers[n] & 0x00FF0000) >> 16);
fprintf(outfile, "%c", (headers[n] & (unsigned int) 0xFF000000) >> 24);
}

fprintf(outfile, "%c", 1);fprintf(outfile, "%c", 0);
fprintf(outfile, "%c", 24);fprintf(outfile, "%c", 0);

for (n = 7; n <= 12; n++){
fprintf(outfile, "%c", headers[n] & 0x000000FF);
fprintf(outfile, "%c", (headers[n] & 0x0000FF00) >> 8);
fprintf(outfile, "%c", (headers[n] & 0x00FF0000) >> 16);
fprintf(outfile, "%c", (headers[n] & (unsigned int) 0xFF000000) >> 24);
}

//Actual writing of data begins here:
for(y = 0; y <= height - 1; y++){
for(x = 0; x <= width - 1; x++){
if(x%2 == 1 && y%2 == 1){
if(x/2+1 == xspecial && y/2+1 == yspecial) RED;
else{
if(MAZE[x/2+1][y/2+1].in) WHITE; else BLACK;
}
}else if(x%2 == 0 && y%2 == 0){
BLACK;
}else if(x%2 == 0 && y%2 == 1){
if(MAZE[x/2+1][y/2+1].left) BLACK; else WHITE;
}else if(x%2 == 1 && y%2 == 0){
if(MAZE[x/2+1][y/2+1].up) BLACK; else WHITE;
}
}
if (extrabytes){ // See above - BMP lines must be of lengths divisible by 4.
for (n = 1; n <= extrabytes; n++){
fprintf(outfile, "%c", 0);
}
}
}
printf("file printed: %s\n", filename);
fclose(outfile);
return;
}

最佳答案

在 C 中,bool 并不表示类型,除非您使用 C99 并包含 stdbool.h

struct cell {
//I have no idea why it wanted the ',' there
,bool in, up, left;

所以它不需要 ,,它试图告诉你它不知道 bool 是什么。

关于需要 C 标识符吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9829680/

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