javascript - 对象值 Extjs4 的 Celleditor

Question

我正在寻找如何执行此操作的最佳解决方案。我有什么:

// model
Ext.define("User", {
    extend: "Ext.data.Model",
    fields: [
        {name: "id", type: "int"},
        {name: "name"},
        {name: "description", type: "string"}
    ]
});
// store with data
var oStore = new Ext.data.Store({
    model: "User",
    data: [
        {id: 1, name: {name:"John"}, description: "Fapfapfap"},
        {id: 2, name: {name:"Danny"}, description: "Boobooboo"},
        {id: 3, name: {name: "Tom"}, description: "Tralala"},
        {id: 4, name: {name:"Jane"}, description: "Ololo"},
    ]
});
// and finally I have a grid panel
Ext.create("Ext.grid.Panel", {
    columns: [
        {dataIndex: "id", header:"ID"},
        {
            dataIndex: "name", 
            header: "Name", 
            renderer: function(value){return value.name;}, 
            editor: "textfield"},
        {dataIndex: "description", header: "Description", flex: 1, editor: "htmleditor"}
    ],
    plugins: [new Ext.grid.plugin.CellEditing({clicksToEdit: 2})],
    store: store,
    renderTo: document.body
});​

当我双击一个单元格时，我在编辑器字段中看到 [object] Object，当我输入有效值时，我在网格中看到空单元格。

所以，问题是——我如何设置 celleditor 来获取数据而不是从 record.name 而是从 record.name.name？

Answer 1

您可以覆盖模型上的get 和set 方法，因此将支持多级字段名称。以下是实现示例。

Ext.define("User", {
    extend: "Ext.data.Model",
    fields: [
        {name: "id", type: "int"},
        {name: "name"},
        {name: "description", type: "string"}
    ],
    get: function(key) {
        if (Ext.isString(key) && key.indexOf('.') !== -1) {
            var parts = key.split('.');
            var result = this.callParent([ parts[0] ]);
            return result[parts[1]];
        }
        return  this.callParent(arguments);
    },
    set: function(key, value) {
        if (Ext.isString(key) && key.indexOf('.') !== -1) {
            var parts = key.split('.');
            var result = this.get(parts[0]);
            result[parts[1]] = value;

            this.callParent([ parts[0], result ]);
            return;
        }
        this.callParent(arguments);
    }
});

我不确定商店是否检测到对 name.name 字段所做的更改。如果不是，您可能还应该将记录标记为脏。

工作样本:http://jsfiddle.net/lolo/dHhbR/2/