c - 当使用 scanf 获取整数和 char 值时，程序会跳过 scanf

Question

这个问题已经有答案了:

Why scanf is behaving weird for char input? (5 个回答)

Does scanf() take '\n' as input leftover from previous scanf()? (1 个回答)

已关闭 9 年前。

#include <stdio.h>


int multiple(int num1,int num2){
    return (num1*num2);
}

int add(int num1, int num2){
    return (num1+num2);
}
/*&x points to its value space *x points to its memory space*/
int main(){

    int num1,num2,ans;
    char func;

    printf("First number => ");
    scanf("%d",&num1);
    printf("Second number => ");
    scanf("%d",&num2);

    printf("Please Enter + for addition, or * for multiplication => ");
    scanf("%c",&func);

    if (func == '*'){
        ans = multiple(num1,num2);
    }else if(func == '+') {
        ans = add(num1,num2);
    }else {
        printf("Sorry, invalid operation");
    }

    printf("Ans : %d",ans);
    return 0;
}

当我运行程序时，它会提示我输入第一个和第二个数字，但它不会提示我输入字符 scanf("%c",&func);没有被执行。

我的输出-------------------------------------------------------- --------------------:

$ ./p8t3
First number => 23
Second number => 32
Please Enter + for addition, or * for multiplication => Sorry, invalid operationAns : 2665616


Answer 1

在扫描 + 或 * 运算符时，进行如下更改:

printf("Please Enter + for addition, or * for multiplication => ");
scanf(" %c",&func);         //use a space before '%c'