javascript - 通过引用传递全局变量并修改引用变量

Question

什么是正确的做法...

var array1 = []
var array2 = []

function doIt(arg){
    var myArray;

    if(arg == 1){
        myArray = array1
    }else if(arg == 2){
        myArray = array2
    }

    myArray.push('test');

}

doIt(1); //array1 should now be ['test'] but it's empty

Answer 1

除了四个小语法缺陷外，您的代码还可以:http://jsfiddle.net/hk9Md/

var array1 = []; // <-- added semi-colon
var array2 = []; // <-- added semi-colon

function doIt(arg){
    var myArray;

    if (arg == 1) {
        myArray = array1; // <-- added semi-colon
    } else if (arg == 2) {
        myArray = array2; // <-- added semi-colon
    }
    myArray.push('test');
}
doIt(1);
alert(array1[0]); // produces 'test'