c - 显示 8 位十六进制偏移量 0x？

Question

到目前为止，我只致力于第一个显示十六进制偏移量“0”的工作，我正在尝试找到一种方法让程序打开文件并显示带有前导 0x 指示符的 8 位十六进制偏移量。我试图让它运行这样的事情:

----------------------------------------------------------------------------- 
 offset      0  1  2  3   4  5  6  7   8  9  a  b   c  d  e  f  ascii
-----------------------------------------------------------------------------
0x00000000
0x00000010 
0x00000020

等等...

任何提示/建议都会很棒。另外，我也在寻找一种“更干净”的方式来显示横幅，而不必 printf 单独的行等等。

所以，我的问题是:

1. 如何让程序显示以 0x 开头的十六进制偏移量。我尝试插入该部分的代码，但我无法完全确定如何插入，因此任何提示将不胜感激。
2. 有没有更简洁的方式来显示标题？

非常感谢。

#include <stdio.h>
#include <stdlib.h>
#include <sys/ioctl.h>


int main(int argc, char** argv)
{
    struct winsize terminal;
    FILE* fp;
    int a, c, column, row, lines;

    ioctl(0, TIOCGWINSZ, &terminal, argv[2]);

    fp = fopen(argv[1], "r");                          //set open for argv[1] and set it to read mode
    column = terminal.ws_col;
    row = terminal.ws_row;
    lines = atoi(argv[2]);

    // printf("Rows are: %d\n", row);
    // printf("Columns are: %d\n", column);

    if (argc < 3)                                      //Argument checking, at least three to run
    {
        printf("You need atleast 3 arguments to run!\n");
        exit(1);
    }

    if (fp == NULL)
    {
        fprintf(stderr, "Error opening '%s'.\n", argv[1]);             //if not file is specified then close program and give an error
        exit(1);
    }
    c = fgetc(fp);                                //set c to fgetc

    if (column < 80 || row < 20)                               //if temrinal window is less than 80x20, display an error and exit
    {
        printf("Terminal window must be at least 80x20!\n");              //display error and close program if column criteria isn't met
        exit(1);
    }

    /*
    while(!feof(fp))                                   //if file is entered, display a test message (this is where later on I will show hex value)

    {
        printf("Good Job! You picked a file to manipulate!!\n");
        exit(1);
     }
     */
    if (lines == 0)                                       //if 0 is entered for argv[2], display all the lines, 512 byte file
    {
        printf("------------------------------------------------------------------------------\n"); //**this is where I try to display character/hex banner**
        printf("offset      0  1  2  3   4  5  6  7   8  9  a  b   c  d  e  f  ascii\n");
        printf("-------------------------------------------------------------------------------\n");
        for (c == 0x200) ; //**This is where I try to get the 8 digit 0x hex offset**
        {
            fprintf(stdout, "%04x", c);
        }
    }
    else if (lines == 20)
    {
        printf("This will print out 20 lines\n");
    }
    else if (lines == 30)
    {
        printf("This will print out 30 lines\n");
    }
    else
    {
        printf("Please Enter a Valid Number!\n");
    }

    fclose(fp);                                        //close fp

    return 0;
}

Answer 1

尝试

printf("0x%08x\n", 0xDEADBEEF);