c - 如何在C中规范化矩阵？

Question

如何标准化矩阵？

假设我有一个 2x3 矩阵:
1 2 3
4 5 6归一化矩阵为:
1/sqrt(pow(2,2) + pow(3,2)) 2/sqrt(pow(2,2) + pow(3,2)) 3/sqrt(pow(2,2) + pow(3,2))<br/>
4/sqrt(pow(5,2) + pow(6,2)) 5/sqrt(pow(5,2) + pow(6,2)) 6/sqrt(pow(5,2) + pow(6,2))

这是我的示例代码:

#include <stdio.h>
#include <conio.h>
#include <math.h>

int main(){  
    int rows, cols, rowCounter, colCounter, r, c;  
    int initial[100], inputMatrix[100][100], rowSum[100] = {0}, norm[100][100], square[100] = {0};


    printf("Enter size of a matrix\n");
    scanf("%d %d", &rows, &cols);
    printf("Enter matrix of size %dX%d\n", rows, cols);
    /* Input matrix */
    for(rowCounter = 0; rowCounter < rows; rowCounter++){
        for(colCounter = 0; colCounter < cols; colCounter++){
            scanf("%d", &inputMatrix[rowCounter][colCounter]);
        }
    }



    for(r = 0; r < rows; r++)  
       {  
           for(c = 1; c < cols; c++)  
           {  
               float a;  
               a == inputMatrix[r][c];  
                square[r] += pow(a, 2);  
           }  
           printf("%.2lf ", square[r]);  
       }  

        for(rowCounter = 0; rowCounter < rows; rowCounter++)  
       {  
           for(colCounter = 0; colCounter < cols; colCounter++)  
           {  
               norm[rowCounter][colCounter] == (inputMatrix[rowCounter][colCounter]) / sqrt(square[rowCounter]);  
           }  
       }  
       printf("\nNormalized Matrix:\n");  
       for(rowCounter = 0; rowCounter < rows; rowCounter++)  
       {  
           for(colCounter = 0; colCounter < cols; colCounter++)  
           {  
               printf("%.3lf ", norm[rowCounter][colCounter]);  
           }  
           printf("\n");  
       }  

        getch();  
        return 0;  
    }  

Answer 1

为什么在这里使用==:

for(r = 0; r < rows; r++)  
   {  
       for(c = 1; c < cols; c++)  
       {  
           float a;  
           a == inputMatrix[r][c];   //look here
            square[r] += pow(a, 2);  
       }  

应该是:

for(r = 0; r < rows; r++)  
   {  
       for(c = 1; c < cols; c++)  
       {  
           float a;  
           a = inputMatrix[r][c];  
            square[r] += pow(a, 2);  
       }  

这里也一样:

norm[rowCounter][colCounter] == (inputMatrix[rowCounter][colCounter]) / sqrt(square[rowCounter]);

应该是:

norm[rowCounter][colCounter] = (inputMatrix[rowCounter][colCounter]) / sqrt(square[rowCounter]);

这里你应该小心:

int initial[100], inputMatrix[100][100], rowSum[100] = {0}, norm[100][100], square[100] = {0};

您确定要对所有这些声明使用 int 吗？我认为你应该使用 double 或 float 来代替，至少在其中一些中。