c - 打印一个数字的英文单词的程序

Question

我编写了一个程序，要求用户输入两位数，然后打印出该数字的英文单词。示例:

Enter a two digit number: 45
You entered fourty-five

基本上，我所做的就是为数字 10 到 19 放置一个 switch 盒，然后为 10 号使用另一个开关盒，为 1 号使用另一个开关盒。

问题是，输入号码后，由于某种原因，打印后没有显示任何内容您输入了号码:

这是代码:

#include <stdio.h>

int main(void) {
    int Num, Tens, Ones;

    printf("Enter a Two Digit Number: ");
    scanf("%d", &Num);

    printf("You entered the number: ");

    if (10 <= Num && Num >= 19) {
        switch (Num) {
          case 10:  printf("Ten\n");        break;
          case 11:  printf("Eleven\n");     break;
          case 12:  printf("Twelve\n");     break;
          case 13:  printf("Thirteen\n");   break;
          case 14:  printf("Fourteen\n");   break;
          case 15:  printf("Fifteen\n");    break;
          case 16:  printf("Sixteen\n");    break;
          case 17:  printf("Seventeen\n");  break;
          case 18:  printf("Eighteen\n");   break;
          case 19:  printf("Nineteen\n");   break;
        }
    }
    if (20 <= Num && Num >= 99) {
        Tens = Num / 10;
        switch (Tens) {
          case 2:   printf("Twenty");   break;
          case 3:   printf("Thirty");   break;
          case 4:   printf("Fourty");   break;
          case 5:   printf("Fifty");    break;
          case 6:   printf("Sixty");    break;
          case 7:   printf("Seventy");  break;
          case 8:   printf("Eighty");   break;
          case 9:   printf("Ninety");   break;
        }
    }
    Ones = Num % 10;
    if (Ones == 0)
        printf("\n");
    else
    if (1 <= Ones && Ones >= 9) {
        printf("-");
        switch (Ones) {
          case 1: printf("One");        break;
          case 2:   printf("Two");      break;
          case 3:   printf("Three");    break;
          case 4:   printf("Four");     break;
          case 5:   printf("Five");     break;
          case 6:   printf("Six");      break;
          case 7:   printf("Seven");    break;
          case 8:   printf("Eight");    break;
          case 9:   printf("Nine");     break;
        }
        printf("\n");
    }
    return 0;
}

Answer 1

您的条件是错误的，并且在正常执行中将始终为假。

尝试这些修改:

• 10 <= Num && Num >= 19 -> 10 <= Num && Num <= 19
• 20 <= Num && Num >= 99 -> 20 <= Num && Num <= 99
• 1 <= Ones && Ones >= 9 -> 1 <= Ones && Ones <= 9