在C中以日期形式组合4个单独的整数

Question

我有一个程序可以读取 EMSO(一个告诉你出生日期、州、性别和其他一些信息的数字)。它是生成的，是一个 13 位数字。最后一个是控件，前两个是日，后两个是月，后三个是年。我希望程序通过根据 EMSO 和当前计算机日期计算出您的年龄。以下是我到目前为止所写的内容:

#include <stdio.h>
#include <windows.h>

int main (void) 
{
unsigned long long int  emso;
int kontrola;
int a,b,c,d,e,f,g,h,i,j,k,l;
int x,y;
int kraj;

system("cls");  

printf("Enter your EMSO: ");
while(scanf("%lld",&emso)!=1)fflush(stdin);



    while(emso!=-1){

    kontrola=emso%10;
    emso/=10;
    l=emso%10;
    emso/=10;
    k=emso%10;
    emso/=10;
    j=emso%10;
    emso/=10;
    i=emso%10;
    emso/=10;
    h=emso%10;
    emso/=10;
    g=emso%10;
    emso/=10;
    f=emso%10;
    emso/=10;
    e=emso%10;
    emso/=10;
    d=emso%10;
    emso/=10;
    c=emso%10;
    emso/=10;
    b=emso%10;
    emso/=10;
    a=emso%10;

    x= (7*a+ 6*b+ 5*c+ 4*d+ 3*e+ 2*f+ 7*g+ 6*h+ 5*i+ 4*j+ 3*k+ 2*l);
    x=x%11;

    if (x!=0){
        x=11-x;     
    }


    kraj=h*10+i;

    if (x==kontrola){
        printf("\n\nEMSO is legitimate!\n");
        if(j==0){
            printf("\nPerson is MALE\n");
        }
            else if (j==5){
                printf("\nPerson in FEMALE\n");
            }


        if (e==9){
            y=1;
        }

        else if (e==0){
            y=2;
        }

        printf("\nDate of birth: %d%d.%d    %d.%d%d%d%d.\n",a,b,c,d,y,e,f,g);   

        if (kraj >=00 && kraj <10){
            printf("\nPerson was born abroad!\n");
        }

        if (kraj>=10 && kraj < 20){
            printf("\nPerson was born in BiH.\n");
        }

        if(kraj >=20 && kraj < 30){
            printf("\nPerson was born in Montenegro.\n");
        }

        if (kraj >= 30 && kraj < 40){
            printf("\nPerson was born in Croatia.\n");
            if (kraj == 33){
                printf("\tPerson was born in Zagreb.\n");
            }
        }

        if (kraj >=40 && kraj < 50){
            printf("\nPerson was born in Macedoniji.\n");
        }

        if (kraj >= 50 && kraj < 60){
            printf("\nPerson was born in Slovenia.\n");
        }

        if (kraj >=70 && kraj < 80){
            printf("\nPerson was born in Srbia.\n");
            if (kraj == 71){
                printf("\tPerson was born in Beogerad.\n");
                }
        }

        if (kraj >=80 && kraj < 90){
            printf("\nPerson was born in Vojvodina.\n");
            if(kraj == 80){
                printf("\tPerson was born in Novi Sad.\n");
                }
        }

        if (kraj >=90 && kraj < 100){
            printf("\nPerson was born in Kosovo.\n");
        }
    }

    if (x!=kontrola){
        printf("\nEMSO is NOT legitimate!\n");
    }

    printf("\n");
    system("pause");
    system("cls");  


    printf("Enter your EMSO: ");
    while(scanf("%lld",&emso)!=1)fflush(stdin);
}


return 0;

}

在所有这些困惑中，a 和 b 代表日期，cd 代表月份，efg 代表月份年。

此外，fflush 功能无法正常工作。它破坏了出生印记。

为了更好地理解，这是我的 emso:0701996500037。这是正常日子的结果:EMSO是合法的!

此人是男性

出生日期:1996年1月7日。

此人出生于斯洛文尼亚。

我很高兴。如果我这样写:0701996500037ž，没问题，相同的输出。但是如果我输入z0701996500037，没有任何反应，就像什么也没输入一样。如果我写0701u996500037，验证没问题，但其他都是错误的。地点和出生错误

Answer 1

time 返回自纪元以来的秒数。 mktime 返回其 struct tm * 参数自纪元以来的秒数。因此:

struct tm date = { /* fill tm_year, tm_mon, etc. */ };
double seconds_since_date = difftime(time(0), mktime(&date));

将为您提供自日期以来经过的秒数。 (这不考虑时区。)