c - 增加意外错误

Question

我正在尝试编译这段很长的代码，但是遇到了很多我不明白的错误，这是代码:(我知道它的代码很长并且有很多错误，但我发现很难解决它，尝试过所有日子都没有成功)

    #include<stdio.h>
#include<stdlib.h>

struct Data
{
    int i,j,n;

}typedef Data_t;

struct Next
{
    Data_t d;
    Next_t* next;
}typedef Next_t;

void printMatrix(int** m,int r,int c)
{
    int i,j;
    printf("Matrix created is:\n");
    for (i=0 ; i<r ; i++)
    {
        for( j=0 ; j<c ; j++)
        {
            printf("%d\t",m[(i*r)+j]);
        }
        printf("\n");
    }
}

int calcMatrix(int** m,int r,int c,Next_t** d,Data_t** arr)
{
    int i,j,counter=0;
    printf("Enter values to the Matrix: \n");
    for (i=0; i<r ; i++)
    {
        printf("Enter values to row #%d: ",i+1);
        for(j=0; j<c ; j++)
        {
            scanf("%d",&m[(i*r)+j]);
        }
    }

    printMatrix(m,r,c);
    Next_t* temp1,*temp2;

    for (i=0; i<r ; i++)
    {
        for (j=0 ; j<c ; j++)
        {
            if (m[i][j] == i+j)
            {
                counter++;
                temp1 = (Next_t*)malloc(sizeof(Next_t));
                temp1->d.n = m[i][j];
                temp1->d.i = i;
                temp1->d.j = j;
                temp1->next = NULL;

                if (*d == NULL)     //add new triplet to the list
                    *d = temp1;
                else
                {
                    temp2 = *d;
                    while (temp2->next != NULL)
                        temp2 = temp2->next;
                    temp2->next = temp1;
                }
            }
        }
    }
    if (counter!=0)
    {
        *arr = (Data_t*)malloc(counter*sizeof(Data_t));
        temp2 = *d;
        for (i = 0; i < counter;i++)
        {
            (*arr)[i] = temp2->d;
            temp2 = temp2->next;
        }
    }
    return counter;
}


void main()
{
    int r,c,**m,solution;
    int i;
    Next_t** d;
    Data_t** arr;
    printf("Please enter number of rows for Matrix: ");
    scanf("%d",&r);
    printf("Please enter number of cols for Matrix: ");
    scanf("%d",&c);
    m = (int**)malloc(r*(sizeof(int*)));
    for (i=0 ; i<c ; i++)
    {
        m[i] = (int*)malloc(c*(sizeof(int)));
    }
    solution = calcMatrix(m,r,c,d,arr);
    printf("Size of Array Is: %d",solution);


}

我收到如下错误:

matala0103.c(13): error C2061: syntax error : identifier 'Next_t'
matala0103.c(14): error C2059: syntax error : '}'
matala0103.c(30): error C2143: syntax error : missing ')' before '*'
matala0103.c(30): error C2081: 'Next_t' : name in formal parameter list illegal
matala0103.c(30): error C2143: syntax error : missing '{' before '*'
matala0103.c(30): error C2371: 'Data_t' : redefinition; different basic types
matala0103.c(8) : see declaration of 'Data_t'
matala0103.c(30): error C2143: syntax error : missing ';' before '*'
matala0103.c(30): error C2059: syntax error : ')'
matala0103.c(31): error C2054: expected '(' to follow 'arr'
\matala0103.c(89): error C2065: 'Next_t' : undeclared identifier
matala0103.c(89): error C2297: '*' : illegal, right operand has type 'int *'
matala0103.c(90): error C2275: 'Data_t' : illegal use of this type as an expression
matala0103.c(8) : see declaration of 'Data_t'

非常感谢任何可以帮助我的人!伊泰。

Answer 1

查看输出的第一个警告或错误通常很有帮助，因为后来的错误通常是由第一个错误引发的多米诺骨牌问题造成的。在这种情况下，第一个错误是

matala0103.c(13): error C2061: syntax error : identifier 'Next_t'

意味着编译器无法弄清楚 Next_t 的含义。这是因为您在实际定义它之前引用了它；此时，编译器不知道 Next_t 是什么。如果将类型更改为编译器已经看到的类型，例如 struct Next_t* next; ，它会工作得更好。