c# - 冒泡事件未发生

Question

在下面的代码中，我看到发生了隧道事件，但没有看到发生相应的冒泡事件。为什么会这样？

谢谢，戴夫

<Window x:Class="TestRoutedEvents.Window1"
   xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
   xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
   Title="Window1" Height="300" Width="300"
   PreviewMouseUp="Window_PreviewMouseUp"
   MouseUp="Window_MouseUp">

   <Grid Background="Brown" Margin="30"
         PreviewMouseUp="Grid_PreviewMouseUp"
         MouseUp="Grid_MouseUp">
      <TextBlock Text="Press me" HorizontalAlignment="Center" VerticalAlignment="Center"
         Background="LightGray"
         Padding="3"
         PreviewMouseUp="TextBlock_PreviewMouseUp"
         MouseUp="TextBlock_MouseUp"/>
   </Grid>
</Window>


namespace TestRoutedEvents
{
   /// <summary>
   /// Interaction logic for Window1.xaml
   /// </summary>
   public partial class Window1 : Window
   {
      public Window1()
      {
         InitializeComponent();
      }





      private void TextBlock_PreviewMouseUp(object sender, MouseButtonEventArgs e)
      {
         MessageBox.Show("TextBlock_PreviewMouseUp");
      }

      private void Grid_PreviewMouseUp(object sender, MouseButtonEventArgs e)
      {
         MessageBox.Show("Grid_PreviewMouseUp");
      }

      private void Window_PreviewMouseUp(object sender, MouseButtonEventArgs e)
      {
         MessageBox.Show("Window_PreviewMouseUp");
      }





      private void TextBlock_MouseUp(object sender, MouseButtonEventArgs e)
      {
         MessageBox.Show("TextBlock_MouseUp");
      }

      private void Grid_MouseUp(object sender, MouseButtonEventArgs e)
      {
         MessageBox.Show("Grid_MouseUp");
      }

      private void Window_MouseUp(object sender, MouseButtonEventArgs e)
      {
         MessageBox.Show("Window_MouseUp");
      }
   }
}

Answer 1

实际上事件正在引发，但您无法得到它。原因是消息框在弹出时从窗口中获取了焦点。因此，路由事件链中的 UI 元素将不再接收路由事件。

您可以控制您的窗口并向其中添加事件详细信息以确认它。例如在 xaml 中添加 ListBox 并将其命名为 listBox，然后在每个处理程序中使用此代码

listBox.Items.Add(sender+"\n"+e.RoutedEvent.Name+"\n"+e.RoutingStrategy);