c - 无法初始化结构数组

Question

我正在传递一个指向函数的指针，我想初始化被调用函数中的结构数组，并想使用该数组主函数。但我无法在主函数中获取它。这是我的代码:

typedef struct _testStruct
{
    int a;
    int b;
} testStruct;

void allocate(testStruct** t)
{
    int nCount = 0;
    int i = 0;
    printf("allocate 1\n");
    t = (testStruct**)malloc(10 * sizeof(testStruct));
    for(i = 0; i < 10; i++)
    {
        t[i] = (testStruct *) malloc( 10 * sizeof(testStruct));
    }
    for(nCount = 0 ; nCount < 10; nCount++)
    {
        t[nCount]->a = nCount;
        t[nCount]->b = nCount + 1;

        printf( "A === %d\n", t[nCount]->a);
    }

}
int main()
{
    int nCount = 0;
    testStruct * test = NULL;
    int n = 0;
    allocate(&test);
    for(nCount = 0 ; nCount < 10; nCount++ )
    {
        if (test == NULL)
        {
            printf( "Not Allocated\n");
            exit(0);
        }
        //printf("a = %d\n",test[nCount]->a);
        /*printf("a = %d\n",test->a);
        printf("b = %d\n",test->b); */
    }

    return 0;
}

请注意，我必须根据需要将双指针传递给函数。感谢您的帮助。

Answer 1

#include <stdio.h>
#include <stdlib.h>

typedef struct _testStruct 
{ 
    int a; 
    int b; 
} testStruct; 

void allocate(testStruct** t) 
{ 
    int nCount = 0; 
    printf("allocate 1\n"); 
    testStruct *newT = (testStruct*)malloc(10 * sizeof(testStruct)); 
    for(nCount = 0 ; nCount < 10; nCount++) 
    { 
        newT[nCount].a = nCount; 
        newT[nCount].b = nCount + 1; 

        printf( "A === %d\n", newT[nCount].a); 
    }

    *t = newT;

} 
int main() 
{ 
    int nCount = 0; 
    testStruct * test = NULL; 
    allocate(&test); 
    for(nCount = 0 ; nCount < 10; nCount++ ) 
    { 
        printf("a = %d\n",test[nCount].a); 
        printf("a = %d\n",test[nCount].b); 

    } 

    return 0; 
}

应该可以。