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C - 付款计算。不以 $0 结尾

转载 作者:行者123 更新时间:2023-11-30 18:02:39 27 4
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我正在尝试创建付款计算器,但遇到错误,剩余余额为负数而不是 0 美元。这是代码:

int main()
{
double selling, down, intRate, intBal, toBal, payment, loan, loanN, d;
int counter, i;

printf("Cost of item: ");
scanf("%lf", &selling);

printf("Down payment on item: ");
scanf("%lf", &down);

printf("Interest rate: ");
scanf("%lf", &intRate);

printf("Monthly payment: ");
scanf("%lf", &payment);

d= selling * 100.0;
i = d + 0.5;
selling = i / 100.0;

d= down * 100.0;
i = d + 0.5;
down = i / 100.0;

d= payment * 100.0;
i = d + 0.5;
payment = i / 100.0;

counter = 1;

loan = selling - down;

printf("--------------------------------------------------------------\n");
printf("Selling Price = %8.2lf\n", selling);
printf("Down Payment = %8.2lf\n", down);
printf("Amount of Loan = %8.2lf\n", loan);
printf("Annual Interest Rate = %8.2lf\n", intRate);
printf("Monthly Payment = %8.2lf\n", payment);
printf("--------------------------------------------------------------\n");
printf("Pay # Old Balance Payment Interest To Balance New Balance\n");
printf("----- ----------- ------- -------- ---------- -----------\n");

while (loan > 0)
{
if (loan < payment)
{
payment = loan + intBal;
}
printf("%5i %11.2lf %7.2lf ", counter, loan, payment);
intBal = intRate * loan / 12;
printf("%8.2lf ", intBal);
toBal = payment - intBal;
printf("%10.2lf ", toBal);
loanN = loan - toBal;
loan = loanN;
printf("%11.2lf\n", loanN);
counter++;
}
return 0;

最佳答案

在贷款结束时,您将向他们收取两次利息。移动这个

if (loan < payment)
{
payment = loan + intBal;
}

到此行之后

intBal = intRate * loan / 12;

关于C - 付款计算。不以 $0 结尾,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9049675/

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