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c - 如何在C中向链表中执行插入、删除和显示元素?

转载 作者:行者123 更新时间:2023-11-30 17:54:26 25 4
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我正在开发一个我不太熟悉的 C 程序。它可以选择如何处理链接列表。但它有错误。到目前为止,这就是我所拥有的。

#include<stdio.h>
#include<stdlib.h>

struct node
{
int data;
struct node *next;
}*head;



void append(int num)
{
struct node *temp,*right;
temp= (struct node *)malloc(sizeof(struct node));
temp->data=num;
right=(struct node *)head;
while(right->next != NULL)
right=right->next;
right->next =temp;
right=temp;
right->next=NULL;
}



void add( int num )
{
struct node *temp;
temp=(struct node *)malloc(sizeof(struct node));
temp->data=num;
if (head== NULL)
{
head=temp;
head->next=NULL;
}
else
{
temp->next=head;
head=temp;
}
}
void addafter(int num, int loc)
{
int i;
struct node *temp,*left,*right;
right=head;
for(i=1;i<loc;i++)
{
left=right;
right=right->next;
}
temp=(struct node *)malloc(sizeof(struct node));
temp->data=num;
left->next=temp;
left=temp;
left->next=right;
return;
}

int count()
{
struct node *n;
int c=0;
n=head;
while(n!=NULL)
{
n=n->next;
c++;
}
return c;
}


void insert(int num)
{
int c=0;
struct node *temp;
temp=head;
if(temp==NULL)
{
add(num);
}
else
{
while(temp!=NULL)
{
if(temp->data<num)
c++;
temp=temp->next;
}
if(c==0)
add(num);
else if(c<count())
addafter(num,++c);
else
append(num);
}
}



int delete(int num)
{
struct node *temp, *prev;
temp=head;
while(temp!=NULL)
{
if(temp->data==num)
{
if(temp==head)
{
head=temp->next;
free(temp);
return 1;
}
else
{
prev->next=temp->next;
free(temp);
return 1;
}
}
else
{
prev=temp;
temp= temp->next;
}
}
return 0;
}


void display(struct node *r)
{
r=head;
if(r==NULL)
{
return;
}
while(r!=NULL)
{
printf("%d ",r->data);
r=r->next;
}
printf("\n");
}


int main()
{
int i,num;
struct node *n;
head=NULL;
while(1)
{
printf("\nList Operations\n");
printf("===============\n");
printf("1.Insert\n");
printf("2.Display\n");
printf("3.Size\n");
printf("4.Delete\n");
printf("5.Exit\n");
printf("Enter your choice : ");
if(scanf("%d",&i)<=0){
printf("Enter only an Integer\n");
exit(0);
} else {
switch(i)
{
case 1: printf("Enter the number to insert : ");
scanf("%d",&num);
insert(num);
break;
case 2: if(head==NULL)
{
printf("List is Empty\n");
}
else
{
printf("Element(s) in the list are : ");
}
display(n);
break;
case 3: printf("Size of the list is %d\n",count());
break;
case 4: if(head==NULL)
printf("List is Empty\n");
else{
printf("Enter the number to delete : ");
scanf("%d",&num);
if(delete(num))
printf("%d deleted successfully\n",num);
else
printf("%d not found in the list\n",num);
}
break;
case 5: return 0;
default: printf("Invalid option\n");
}
}
}
return 0;
}

最佳答案

我制作了另一个工作程序。看看这个。您可能还有一些补充,也许?

#include <iostream>
#include <conio.h>
using namespace std;

class Node {
int data;
Node* next;
public:
Node() {};
void SetData(int aData) { data = aData; };
void SetNext(Node* aNext) { next = aNext; };
int Data() { return data; };
Node* Next() { return next; };
};

class List {
Node *head;
public:
List() { head = NULL; };
void Display();
void Append(int data);
void Remove(int data);
};

void List::Display() {
Node *tmp = head;
if ( tmp == NULL ) {
cout << "EMPTY" << endl;
return;
}
if ( tmp->Next() == NULL ) {
cout << tmp->Data();
cout << " --> ";
cout << "NULL" << endl;
}
else {
do {
cout << tmp->Data();
cout << " --> ";
tmp = tmp->Next();
} while ( tmp != NULL );
cout << "NULL" << endl;
}
}

void List::Append(int data) {
Node* newNode = new Node();
newNode->SetData(data);
newNode->SetNext(NULL);
Node *tmp = head;
if ( tmp != NULL ) {
while ( tmp->Next() != NULL ) {
tmp = tmp->Next();
}
tmp->SetNext(newNode);
}
else {
head = newNode;
}
}

void List::Remove(int data) {
Node *tmp = head;
if ( tmp == NULL )
return;
if ( tmp->Next() == NULL ) {
delete tmp;
head = NULL;
}
else {
Node *prev;
do {
if ( tmp->Data() == data ) break;
prev = tmp;
tmp = tmp->Next();
} while ( tmp != NULL );
prev->SetNext(tmp->Next());
delete tmp;
}
}

int main() {
List list;
int n[100], i, size;
char choice;
for(i=1; i<=100; i++){
cout<<"Insert[I]\nDisplay[D]\nRemove[R]\n";
cin>>choice;
if (choice=='I'||choice=='i'){
cout<<"Enter the number of nodes: ";
cin>>size;
cout<<"Enter a number to be inserted:\n";
for(i=1; i<=size; i++){
cin>>n[i];
list.Append(n[i]);
}
}
if (choice=='D'||choice=='d'){
cout<<"Elements in the list are: ";
list.Display();
}
if (choice=='R'||choice=='r'){
cout<<"Enter a number to be removed: ";
cin>>n[i];
list.Remove(n[i]);
}
}
getch();
}

关于c - 如何在C中向链表中执行插入、删除和显示元素?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14953213/

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