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c - 读取 C 中的 .dat 文件丢失/重复记录

转载 作者:行者123 更新时间:2023-11-30 17:54:06 28 4
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我正在尝试从 .dat 文件中读取结构...要读取的第一个整数是读数的数量然后有以下结构格式的数据

struct Oven
{
int rec_no;
int temp;
int status;
char string[10];
};

下面是我读取文件的方法

int read_and_process_file()
{
int counter;
FILE *ptr_myfile;
struct Oven my_record;

ptr_myfile=fopen("data.dat","rt");

//for no of readings
fread(&no_of_readings,sizeof(no_of_readings),1,ptr_myfile);


for ( counter=1; counter <= 50; counter++)
{
fread(&my_record,sizeof(struct Oven),1,ptr_myfile);

name=my_record.string;

printf("%d : ",my_record.rec_no);
fprintf(ptr_myfile2,"%d : ",my_record.rec_no);
printf("%d : ",my_record.temp);
printf("%d : ",my_record.status);
printf("%s\n",name);
}

fclose(ptr_myfile);
return 0;
}

但我无法在 25 条之后读取超过 25 条记录,它会不断重复第 25 条记录...

尝试了 fseek,但它跳过了一些记录...有帮助吗?

这是输出图像

更新(Wildplasser)这是数据的前 0x200 字节(看起来确实有点不规则......)

00000000  b8 0b 00 00 00 00 00 00  54 00 00 00 01 00 00 00  |........T.......|
00000010 42 6f 62 00 cd cd cd cd cd cd cd cd 01 00 00 00 |Bob.............|
00000020 4d 00 00 00 00 00 00 00 43 4c 4f 53 45 44 00 cd |M.......CLOSED..|
00000030 cd cd cd cd 02 00 00 00 2e 00 00 00 00 00 00 00 |................|
00000040 43 4c 4f 53 45 44 00 cd cd cd cd cd 03 00 00 00 |CLOSED..........|
00000050 5f 00 00 00 01 00 00 00 48 61 72 72 79 00 cd cd |_.......Harry...|
00000060 cd cd cd cd 04 00 00 00 44 00 00 00 01 00 00 00 |........D.......|
00000070 48 61 72 72 79 00 cd cd cd cd cd cd 05 00 00 00 |Harry...........|
00000080 63 00 00 00 01 00 00 00 4a 69 6c 6c 00 cd cd cd |c.......Jill....|
00000090 cd cd cd cd 06 00 00 00 53 00 00 00 01 00 00 00 |........S.......|
000000a0 4a 61 6d 65 73 00 cd cd cd cd cd cd 07 00 00 00 |James...........|
000000b0 56 00 00 00 00 00 00 00 43 4c 4f 53 45 44 00 cd |V.......CLOSED..|
000000c0 cd cd cd cd 08 00 00 00 49 00 00 00 00 00 00 00 |........I.......|
000000d0 43 4c 4f 53 45 44 00 cd cd cd cd cd 09 00 00 00 |CLOSED..........|
000000e0 53 00 00 00 01 00 00 00 42 6f 62 00 cd cd cd cd |S.......Bob.....|
000000f0 cd cd cd cd 0d 0a 00 00 00 59 00 00 00 00 00 00 |.........Y......|
00000100 00 43 4c 4f 53 45 44 00 cd cd cd cd cd 0b 00 00 |.CLOSED.........|
00000110 00 46 00 00 00 01 00 00 00 4a 69 6c 6c 00 cd cd |.F.......Jill...|
00000120 cd cd cd cd cd 0c 00 00 00 38 00 00 00 00 00 00 |.........8......|
00000130 00 43 4c 4f 53 45 44 00 cd cd cd cd cd 0d 00 00 |.CLOSED.........|
00000140 00 48 00 00 00 00 00 00 00 43 4c 4f 53 45 44 00 |.H.......CLOSED.|
00000150 cd cd cd cd cd 0e 00 00 00 5e 00 00 00 01 00 00 |.........^......|
00000160 00 4a 61 6d 65 73 00 cd cd cd cd cd cd 0f 00 00 |.James..........|
00000170 00 40 00 00 00 01 00 00 00 4a 69 6c 6c 00 cd cd |.@.......Jill...|
00000180 cd cd cd cd cd 10 00 00 00 56 00 00 00 00 00 00 |.........V......|
00000190 00 43 4c 4f 53 45 44 00 cd cd cd cd cd 11 00 00 |.CLOSED.........|
000001a0 00 43 00 00 00 01 00 00 00 4a 61 6d 65 73 00 cd |.C.......James..|
000001b0 cd cd cd cd cd 12 00 00 00 60 00 00 00 01 00 00 |.........`......|
000001c0 00 42 6f 62 00 cd cd cd cd cd cd cd cd 13 00 00 |.Bob............|
000001d0 00 5e 00 00 00 00 00 00 00 43 4c 4f 53 45 44 00 |.^.......CLOSED.|
000001e0 cd cd cd cd cd 14 00 00 00 55 00 00 00 00 00 00 |.........U......|
000001f0 00 43 4c 4f 53 45 44 00 cd cd cd cd cd 15 00 00 |.CLOSED.........|

最佳答案

由于您的代码片段不完整,因此很难准确判断发生了什么,但以下是我注意到的一些事情:

  • 您似乎没有使用读入 no_of_readings,而是尝试读取 50 条记录。由于您不检查 fread 的返回值,因此您的程序只会继续使用上次成功读取的 fread 内容。

  • 如果您不阅读文本,则不应以文本模式打开文件。行结束转换可能会损坏您的数据。使用“rb”代替(同样以文本模式打开的标准 C 方式只是省略 b,t 是非标准的)。

  • 编辑:在 Windows 上,以文本模式读取文件会将 ctrl-z 字节 (26) 解释为文件结尾。这就是为什么您的读取在第 25 条记录之后停止。

  • 直接从结构中读取/写入数据将导致数据文件不可移植。最好手动将结构序列化为字节。

关于c - 读取 C 中的 .dat 文件丢失/重复记录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15173427/

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