c++ - 不知道如何使用 popt 库

Question

全部:

感谢您的帮助。

我是 C 选项解析的新手，现在，我想要的是使用 popt 库来解析每个参数并将它们打印出来。

    #include <iostream>
    #include <string>
    #include <cstring>
    #include <popt.h>

    using namespace std;

    int main(int argc, const char* argv[]){

        char* dt1;
        char* dt2;

        struct poptOption {
               const char * longName; /* may be NULL */
               char shortName;        /* may be ’\0’ */
               int argInfo;
               void * arg;            /* depends on argInfo */
               int val;               /* 0 means don’t return, just update flag */
               char * descrip;        /* description for autohelp -- may be NULL */
               char * argDescrip;     /* argument description for autohelp */
            };
        struct poptOption optionsTable[]={
            {"start",'s',POPT_ARG_STRING,dt1,'s',"The date format should like YYYY-MM-DD.",0},
            {"end",'e',POPT_ARG_STRING,dt2,'e',"The date format should like YYYY-MM-DD.",0},
            //~ POPT_AUTOHELP
            //~ {NULL,0,0,NULL,0}
            };

        poptContext optCon;
        optCon = poptGetContext (0, argc, argv, optionsTable, 0);

            const char* portname = poptGetArg(optCon);
        cout<<portname<<endl;
        return 0;
}

当我编译它时，出现错误:

test.cpp: In function ‘int main(int, const char**)’
test.cpp:27: warning: deprecated conversion from string constant to ‘char*’
test.cpp:27: warning: deprecated conversion from string constant to ‘char*’
test.cpp:30: error: cannot convert ‘main(int, const char**)::poptOption*’ to ‘const poptOption*’ for argument ‘4’ to ‘poptContext_s* poptGetContext(const char*, int, const char**, const poptOption*, unsigned int)’

Answer 1

我认为您不应该在程序中定义 struct poptOption。该结构应该在 popt 包含文件中为您定义。尝试删除该结构定义。

注意，我认为您还需要取消注释此行:

    //~ {NULL,0,0,NULL,0}