c - 在 C 中打印不同格式的文件时需要帮助吗？

Question

我正在开发一个项目，我必须在运行时动态填充的文件中捕获 ALIVE/SEARCH/BYEBYE 的 uuid 出现次数的统计信息(可以是全部 3 个、每个 2 个的组合或单独一个)。

我可以打印所有 3 种组合，但不能打印 1 种或 2 种组合，例如

如果我的input.txt是这样的:

uuid:22314754-a597-490b-8a93-02cfae01036b ALIVE 16
uuid:22314754-a597-490b-8a93-02cfae01036b BYEBYE 8
uuid:22314754-a597-490b-8a93-02cfae01036b SEARCH 8
uuid:50e65653-7525-485d-83bf-d293558c4264 ALIVE 32
uuid:50e65653-7525-485d-83bf-d293558c4264 BYEBYE 8
uuid:50e65653-7525-485d-83bf-d293558c4264 SEARCH 132
uuid:55076f6e-6b79-4d65-6497-180373763bc1 ALIVE 113
uuid:55076f6e-6b79-4d65-6497-180373763bc1 BYEBYE 112
uuid:55076f6e-6b79-4d65-6497-180373763bc1 SEARCH 111
uuid:T0100203354 ALIVE 1
uuid:T0100203354 BYEBYE 2
uuid:T0100203354 SEARCH 3

我的代码:

#include<stdio.h>
#include<string.h>

struct uid
{
    char uid_val[100];
    char state[100];
    int temp_count;
    int alive_count;
    int search_count;
    int bye_count;

} UID[100];

int main()
{
    char str[100];
    int i = 0;

    int line = 0;

    char temp_val[100] = "waseem";

    FILE *fp1 = fopen("input.txt","r");
    FILE *fp2=fopen("output.txt","w");

    printf("init value is %s \n",temp_val);
    while(!feof(fp1))
    {
        fscanf(fp1,"%s %s %d",UID[i].uid_val,UID[i].state,&UID[i].temp_count);

        int ret = 0;
        ret=strcmp(UID[i].uid_val,temp_val);
        if (ret!=0)
        {
            printf("new UID_val is %s\n",UID[i].uid_val);

        }
        else
        {
        }

        temp_val[0] = '\0';
        strcpy(temp_val,UID[i].uid_val);


        if(strcmp(UID[i].state,"ALIVE")==0)
        {
            UID[i].alive_count = UID[i].temp_count;
        }
        else if(strcmp(UID[i].state,"BYEBYE")==0)
        {
            UID[i].search_count = UID[i].temp_count;
        }
        else
        {
            UID[i].bye_count = UID[i].temp_count;
        }


        line++;

        if(line%3 == 0)
        {
            i++;
        }
    }


    int n = 0;
    //fp2=fopen("output.txt","w");

    if (fp2==NULL)
    {
        printf("cant output to file\n");
    }
    else
    {
        fprintf(fp2,"Device ID\t\t\t\t\tALIVE\tBYEBYE\tSEARCH\n");
        for(n = 0;n < i;n++)
        {
            fprintf(fp2,"%s\t%d\t%d\t%d\n",UID[n].uid_val,UID[n].alive_count,UID[n].search_count,UID[n].bye_count);
        }
    }




        fclose(fp1);
        fclose (fp2);

        return 0;
    }
}

给出以下输出:(output.txt)

Device ID ALIVE BYEBYE SEARCH
uuid:22314754-a597-490b-8a93-02cfae01036b 16 8 8
uuid:50e65653-7525-485d-83bf-d293558c4264 32 8 132
uuid:55076f6e-6b79-4d65-6497-180373763bc1 113 112 111
uuid:T0100203354 1 2 3

我想概括代码，使得 uuid 出现次数不必全部为 3 个(ALIVE/SEARCH/BYEBYE)，出现次数可以是任意组合，并且代码应该可以工作。例如，当 input.txt 包含以下内容时，我的代码给出错误结果:

uuid:22314754-a597-490b-8a93-02cfae01036b BYEBYE 8
uuid:22314754-a597-490b-8a93-02cfae01036b SEARCH 8
uuid:50e65653-7525-485d-83bf-d293558c4264 ALIVE 32
uuid:50e65653-7525-485d-83bf-d293558c4264 BYEBYE 8
uuid:55076f6e-6b79-4d65-6497-180373763bc1 ALIVE 113
uuid:55076f6e-6b79-4d65-6497-180373763bc1 BYEBYE 112
uuid:55076f6e-6b79-4d65-6497-180373763bc1 SEARCH 111
uuid:T0100203354 BYEBYE 2

我使用 ubuntu 作为 gcc/g+ 编译器。

Answer 1

这是我给你的建议。使用不同的结构来存储输出，这将降低循环的复杂性。检查您的 uid 与之前收到的 uid，并相应地分配给输出结构。你最好检查一下我重写的代码。它适用于两种输出

#include<stdio.h>
#include<string.h>

struct uid
{
    char uid_val[100];
    char state[100];
    int temp_count;

} UID[100];

struct uid1
{
    char uid_val[100];
    int alive_count;
    int search_count;
    int bye_count;

} UID_NEW[100];

int main()
{
    char str[100];
    int i = 0;
    int j=0;
    FILE *fp1 = fopen("input.txt","r");
    FILE *fp2=fopen("output.txt","w");
    while(!feof(fp1))
    {
        fscanf(fp1,"%s %s %d",UID[i].uid_val,UID[i].state,&UID[i].temp_count);
        if(i>0)
        {
            if(strcmp(UID_NEW[j].uid_val,UID[i].uid_val)!=0)
            {
                j++;
            }
        }
        strcpy(UID_NEW[j].uid_val,UID[i].uid_val);

        if(strcmp(UID[i].state,"ALIVE")==0)
        {
            UID_NEW[j].alive_count = UID[i].temp_count;
        }
        else if(strcmp(UID[i].state,"BYEBYE")==0)
        {
            UID_NEW[j].search_count = UID[i].temp_count;
        }
        else
        {
            UID_NEW[j].bye_count = UID[i].temp_count;
        }

        i++;
    }
    int n = 0;
    if (fp2==NULL)
    {
        printf("cant output to file\n");
    }
    else
    {
        fprintf(fp2,"Device ID\t\t\t\t\tALIVE\tBYEBYE\tSEARCH\n");
        for(n = 0;n <= j;n++)
        {
            fprintf(fp2,"%50s\t%3d\t%3d\t%3d\n",UID_NEW[n].uid_val,UID_NEW[n].alive_count,UID_NEW[n].search_count,UID_NEW[n].bye_count);
        }
    }
    fclose(fp1);
    fclose (fp2);
    return 0;
}