c - 删除 char 数组中的第一个标记并将其余部分保留在 C 中

Question

因此，如果我在 C 中有以下字符数组:

"a    b       c" // where "a", "b", and "c" can be char arrays of any length and the
                 // space between them can be of any length

如何删除“a”标记，但将其余的“b c”存储在字符指针中？

到目前为止，我已经实现了以下不起作用的方法:

char* removeAFromABC(char* a, char* abc) {
    char* abcWithoutA[MAXIMUM_LINE_LENGTH + 1];

    int numberOfCharsInA = strlen(a);

    strcpy(abcWithoutA, (abc + numberOfCharsInA));
    return abcWithoutA;
}

Answer 1

发帖者澄清他的需求后编辑答案:

char* removeAFromABC(char* a, char* abc)
{
  char *t;

  t = strstr(abc, a);   /* Find A string into ABC */
  if (t)                /* Found? */
    for (t+=strlen(a);(*t)==' ';t++);   /* Then advance to the fist non space char */
  return t;   /* Return pointer to BC part of string, or NULL if A couldn't be found */
}